The sum is 160/(1-r)=1280 where r is the common ratio,
1/(1-r)=1280/160=8
Inverting we get 1-r=1/8, r=7/8.
Answer: $163.85
Explanation:
1) Data:
Purchase price: $ 113.00
mark up: 45%
2) Formula
selling price = purchase price + mark up
mark up = % * purchase price
3) Solution
mark up = 45% * $ 113.00 = 0.45 * $ 113.00 = $50.85
selling price = $ 113.00 + $ 50.85 = $ 163.85
Answer: $ 163.85
20 mitiplay by 18 thats the answer
If you ever have a polynomial with a solution of bi, then it will also have a solution of -bi. Imaginary solutions always come in pairs.
So, yes, you could have a polynomial with solutions 2i and 5i, as long as -2i and -5i are also solutions.
(x-2i)(x+2i)(x-5i)(x+5i) would be the most basic polynomial you could form.
(x-2i)(x+2i)(x-5i)(x+5i) = (x^2+4)(x^2+25)
= x^4 + 29x^2 + 100
So the equation would be x^4 + 29x^2 + 100 = 0.
Now, if the question was "only the solutions of 2i and 5i and no others," then the answer is no, for the previously stated reason.
Answer:
NOT found in obtuse triangles
Step-by-step explanation:
you only talk about hypotenuse, adjacent, and opposite in right triangle
