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exis [7]
3 years ago
15

Grayson charges $35 per hour plus a $35 administration fee for tax preparation. Ian charges $45 per hour plus a $15 administrati

on fee. If h represents the number of hours of tax preparation, for what number of hours does Grayson charge more than Ian?
h less-than 2
h greater-than 2
h less-than 5
h greater-than 5
Mathematics
2 answers:
NikAS [45]3 years ago
8 0

Answer:

h less-than 2

Step-by-step explanation:

frosja888 [35]3 years ago
6 0

Answer:

h less-than 2

Step-by-step explanation:

Let

h ---> the number of hours

y ---> the total charge in dollars

we know that

The linear equation is slope intercept form is equal to

y=mh+b

where

m is the slope or unit rate of the linear equation

b is the y-intercept or initial value of the linear equation

we have

<em>Grayson</em>

The slope is equal to m=\$35\ per\ hour

The y-intercept is b=\$35

so

The total charge is equal to

y=35h+35 ----> equation A

<em>Ian</em>

The slope is equal to m=\$45\ per\ hour

The y-intercept is b=\$15

so

The total charge is equal to

y=45h+15 ----> equation B

For what number of hours does Grayson charge more than Ian?

The inequality that represent this situation is

35h+35 > 45h+15

solve for x

Group terms

35-15 > 45h-35h

20 > 10h

Divide by 10 both sides

2 > h

Rewrite the expression

h< 2\ hours ----> h less than 2 hours

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A local Charity receives 1/3 of funds raised during a craft fair and bake sale. The total amount given to the charity was $137.4
Fed [463]

Answer:

The bake sale raised $412.35

Step-by-step explanation:

* Lets explain how to solve the problem

- A local Charity receives 1/3 of funds raised during a craft fair and

 bake sale

∴ The total amount given to the charity = 1/3 × the funds raised during

  a craft fair and bake sale

- The total amount given to the charity was $137.45

∴ The 1/3 of of funds raised during a craft fair and bake sale is $137.45

- Lets substitute the The total amount given to the charity in the

 equation above to find the funds raised during the bake sale

∴ 137.45 = 1/3 × the funds raised during the bake sale

- Multiply the both sides by 3

∴ 3 × 137.45 = the funds raised during the bake sale

∴ The funds raised during the bake sale = 412.35

* The bake sale raised $412.35

6 0
3 years ago
GIVING OUT BRAINLIST QUICK! NUMBER 6
Sunny_sXe [5.5K]

Answer:

40

Step-by-step explanation:

AREA=LW

L₁W₁=40

L₂W₂=160

x(L₁W₁)=L₂W₂

x(L₁W₁)=L₂W₂

x(40)=160

x=40

7 0
2 years ago
Ben wrote a check for $52 that was more than his account balance. The bank charges $25 for bounced checks and the local business
MrRa [10]
$97

This is because he will owe the amount of the check $52, plus he will also owe the two fees which will total $45
7 0
2 years ago
Read 2 more answers
What is an exponent​
ValentinkaMS [17]
It refers to the number of times a number is being multiplied by itself ... Ex: two to the fourth power
4 would be the exponent
6 0
3 years ago
How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con
sladkih [1.3K]

65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

0-1 and 0-1-1

Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

2x + 3y = 18

Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

Learn more about Sequences on:

brainly.com/question/12246947

#SPJ4

8 0
2 years ago
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