I think it would be 3.75 x 10^1.
Step-by-step explanation:
100% = 33,000 ft
1% = 100%/100 = 33000/100 = 330 ft
6% = 1% × 6 = 330 × 6 = 1980 ft
that means the plane has to go down 1980 ft to
33,000 - 1980 = 31,020 ft
and then it goes up by 5000 ft :
31,020 + 5000 = 36,020 ft
that is the final altitude.
Answer:
3sq units
Step-by-step explanation:
bxh = 2x3=6
6/2=3
681 tsp/48 tsp = 14.1875
If you round down, you get 14 servings.
You have to estimate the slope of the tangent line to the graph at <em>t</em> = 10 s. To do that, you can use points on the graph very close to <em>t</em> = 10 s, essentially applying the mean value theorem.
The MVT says that for some time <em>t</em> between two fixed instances <em>a</em> and <em>b</em>, one can guarantee that the slope of the secant line through (<em>a</em>, <em>v(a)</em> ) and (<em>b</em>, <em>v(b)</em> ) is equal to the slope of the tangent line through <em>t</em>. In this case, this would be saying that the <em>instantaneous</em> acceleration at <em>t</em> = 10 s is approximately equal to the <em>average</em> acceleration over some interval surrounding <em>t</em> = 10 s. The smaller the interval, the better the approximation.
For instance, the plot suggests that the velocity at <em>t</em> = 9 s is nearly 45 m/s, while the velocity at <em>t</em> = 11 s is nearly 47 m/s. Then the average acceleration over this interval is
(47 m/s - 45 m/s) / (11 s - 9 s) = (2 m/s) / (2 s) = 1 m/s²