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3 years ago

What is the general form of the equation of the line shown?

Mathematics

2 answers:

Mrac [35]3 years ago

7 0

Answer:

B. x - y = 0

Step-by-step explanation:

ZanzabumX [31]3 years ago

5 0

Check the picture below. So let's use those two points on the line.

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{3}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-0}{3-0}\implies \cfrac{3}{3}\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=1(x-0)\implies y=x \\\\\\ -x+y=0\implies \stackrel{\textit{standard form}}{x-y=0}$

bearing in mind that the standard form is also a general form.

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

You might be interested in

Find the quotient of (11 ^ 18)/(11 ^ 3)

astraxan [27]

Answer:

The first choice, $11^{15}$ .

Step-by-step explanation:

The numerator, $11^{18}$ , is equivalent to eighteen " $11$ " multiplied together:

$11^{18} = \underbrace{11 \times 11 \times 11 \times 11 \times \cdots \times 11 \times 11}_{\text{$18$ in total}}$ .

On the other hand, the denominator, $11^{3}$ , is equivalent to three " $11$ " multiplied with one another:

$11^{3} = 11 \times 11 \times 11$ .

Dividing $11^{18}$ by $11^{3}$ would eliminate three " $11$ " from the numerator:

$\begin{aligned}& \frac{11^{18}}{11^{3}} \\ =\; & \frac{(11 \times 11 \times 11) \times \overbrace{11 \times \cdots \times 11}^{\text{$(18 - 3)$ in total}}}{(11 \times 11 \times 11)} \\ =\; & \overbrace{11 \times \cdots \times 11}^{\text{$15$ in total}} \\ =\; & 11^{15}\end{aligned}$ .

In general, dividing an expression by $y^{b}$ ( $y \ne 0$ ) is equivalent to multiplying that expression by $y^{-b}$ .

For example, in this question, dividing $11^{18}$ by $11^{3}$ would be equivalent to multiplying $11^{18}\!$ by $11^{-3}$ . In other words:

$\begin{aligned}& \frac{11^{18}}{11^{3}} \\ =\; & 11^{18} \times 11^{-3} \\ =\; & 11^{18 - 3} \\ =\; & 11^{15}\end{aligned}$ .

6 0

2 years ago

Please Help!!!!!!!!!!!!!!!!

trapecia [35]

Answer: ( D) 998 is the greatest three digit positive integer

Step-by-step explanation: Your welcome.

7 0

2 years ago

Please help with these questions (no links)

seraphim [82]

If the cakes are circles,
3.14(4)2= 50.24
3.14(5)2= 78.5
78.5-50.24= 28.26

#1 is 28.26

3 0

2 years ago

a square garden with a side of 150m has a square swimming pool in the very center with a side length of 25m calculate the area o

marta [7]

Answer: 21,875 sqm

Step-by-step explanation:

Step 1:

Find the gross area of the garden.

Square 150m = 22,500 sqm.

Step 2:

Find the area of the pool.

Square 25m = 625 sqm.

Step 3:

Subtract the area of the pool from the gross area of the garden

to find the net area of the garden.

22,500 - 625 = 21,875 sqm.

Warning:

Do not subtract the side length of the swimming pool from the side length

of the garden before squaring.

7 0

3 years ago

A toll collector on a highway receives $8 for trucks and $5 for sedans. At the end of a 3-hour period, she collected $208.

Vilka [71]

Answer:

The number of trucks and sedans can be

(0 trucks ,26 sedans)

(8 trucks ,21 sedans)

(24 trucks ,11 sedans)

(25 trucks ,1 sedans)

(32 trucks ,6 sedans)

(16 trucks ,16 sedans)

Step-by-step explanation:

Given:

The cost for trucks =$5

The cost for sedans =$8

The total amount collected = $208

To Find:

Number of trucks and sedans passed through the toll booth =?

Solution:

Let the number of trucks be x and the number of sedans be y

Then

5x + 8y = 208-------------------------------(1)

By Trail and error method

5(0) + 8(26) = 208

5(8) + 8(21) = 208

5(24) +8(11) =208

5(25) + 8(1) = 208

5(32) + 8(6) =208

5(16) + 8(16) = 208

8 0

3 years ago