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Vlada [557]
3 years ago
5

What is the general form of the equation of the line shown?

Mathematics
2 answers:
Mrac [35]3 years ago
7 0

Answer:

B. x - y = 0

Step-by-step explanation:

ZanzabumX [31]3 years ago
5 0

Check the picture below.  So let's use those two points on the line.

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{3}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-0}{3-0}\implies \cfrac{3}{3}\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=1(x-0)\implies y=x \\\\\\ -x+y=0\implies \stackrel{\textit{standard form}}{x-y=0}

bearing in mind that the standard form is also a general form.

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

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sveticcg [70]

Answer: y=4x

Step-by-step explanation:

A direct variation equation has the form:

y=kx

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By definition, we know that the perimeter of the square is the sum of the lengths of its sides or, as all the sides are equal, you can multiply the lenght of any side by 4.

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3 years ago
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Read 2 more answers
Is the the right answer???
Fynjy0 [20]
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