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balu736 [363]
3 years ago
6

Evaluate each expression when s=9 and t=12 1. 3(3t + s) 2. 2s - t

Mathematics
1 answer:
kvasek [131]3 years ago
5 0

1.) 3 (3t + s)

distribute

9t + 3s

plug in the variables

9 ( 12 ) + 3 ( 9 )

108 + 27

135

2.) 2s - t

plug in the variables

2 ( 9 ) - 12

18 - 12

6

I hope this helped and i sincerely hope that this was the brainliest answer!

have a nice day

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the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu
Snowcat [4.5K]
It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}
\\
\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}
\\
\\=\frac{-42\pm \sqrt{1764}}{-19.6}
\\
\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}
\\
\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}
\\
\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
8 0
3 years ago
PLEASE HELP, ITS TIMED HURRY >>>>
tresset_1 [31]

Answer:2

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
35. V112 + V63<br> How do I solve this please
konstantin123 [22]

Answer: 175V

Step-by-step explanation:

V112+V63=112v+63V

Add them together because the terms are like terms. Therfore, 112V+63V=175V

4 0
3 years ago
Divide line segments
ser-zykov [4K]

tis noteworthy that the segment contains endpoints of A and C and the point B is in between A and C cutting the segment in a 1:2 ratio,

\bf \textit{internal division of a line segment using ratios} \\\\\\ A(-9,-7)\qquad C(x,y)\qquad \qquad \stackrel{\textit{ratio from A to C}}{1:2} \\\\\\ \cfrac{A\underline{B}}{\underline{B} C} = \cfrac{1}{2}\implies \cfrac{A}{C}=\cfrac{1}{2}\implies 2A=1C\implies 2(-9,-7)=1(x,y)\\\\[-0.35em] ~\dotfill\\\\ B=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] ~\dotfill

\bf B=\left(\cfrac{(2\cdot -9)+(1\cdot x)}{1+2}\quad ,\quad \cfrac{(2\cdot -7)+(1\cdot y)}{1+2}\right)~~=~~(-4,-6) \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(2\cdot -9)+(1\cdot x)}{1+2}=-4\implies \cfrac{-18+x}{3}=-4 \\\\\\ -18+x=-12\implies \boxed{x=6} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(2\cdot -7)+(1\cdot y)}{1+2}=-6\implies \cfrac{-14+y}{3}=-6 \\\\\\ -14+y=-18\implies \boxed{y=-4}

6 0
3 years ago
Jessica and Martha each have a bag of cookies with unequal quantities. They have 30 cookies total between the two of them. Each
antiseptic1488 [7]

Answer:

x^2 - 30 + 224 ≥ 0  

the amount of cookies Jessica has more than Martha is at least two

Step-by-step explanation:

J + M = 30

x - 12 < 80

8 0
3 years ago
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