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3 years ago

The amount of force needed to keep a 0.1 kg basketball moving at a constant speed of 6 m/s on friction less ice is ____ Newtons

1 answer:

7 0

Basketball has a mass of 0.1kg
m = 0.1 kg
The basket ball is moving at constant speed, this shows that it is not accelerating. So, acceleration is zero
a = 0m/s²
The constant speed is 6m/s
v = 6m/s
So, force to keep it moving with this constant speed can be calculated using Newton second law of motion
F = ma
F = m × 0
F = 0N
So, since the basket ball is moving at constant speed, then, the force need to keep the ball moving is 0N.

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Casey paid a total of $24.00 for 4 shirts. If each shirt costs the same amount, what is the price of one

Crank

Answer:

Step-by-step explanation:

6 x 4 = 24

7 0

2 years ago

PLEASE HELP!!!!!!!!!!!!!

Anvisha [2.4K]

Answer:

60.7

Step-by-step explanation:

multiply 7 3/4 by 4, then multiply 4 5/8 by 4, then 2 4/5 by 4, then add it all together to get your answer.

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3 years ago

In the figure below which term best describes point X?

Dmitrij [34]

The answer is B. centroid, which is the intersection of three medians of the triangle's sides.

Let's look into other answers as well:

A. Circumcenter

It is the point where three perpendicular bisector meet, and is not correct as we can see there is no indication of right angles.

The first photo is what a circumcenter looks like:

C. Incenter

It is the point where the angle bisectors of the triangles meet, which is not indicated in the photo as well.

The second photo is what a incenter looks like:

D. Orthocenter

It is a point where the altitudes of a triangle intersect, and is not indicated by the figure.

The second photo is what a Orthocenter looks like:

Therefore the answer is B. Centroid.

Hope it helps!

3 0

2 years ago

Two number cubes are tossed. What is P(4, 6)?<br><br> O.1/6<br> O.1/12<br> O.1/3<br> O.1/36

Bezzdna [24]

The value of P(4, 6) when the two number cubes are tossed is 1/36

<h3>How to determine the probability?</h3>

On each number cube, we have:

Sample space = {1, 2, 3, 4, 5, 6}

The individual probabilities are then represented as:

P(4) =1/6

P(6) =1/6

The value of P(4, 6) when the two number cubes are tossed is:

P(4, 6) = P(4) * P(6)

This gives

P(4, 6) = 1/6 * 1/6

Evaluate

P(4, 6) = 1/36

Hence, the value of P(4, 6) when the two number cubes are tossed is 1/36