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3 years ago

The amount of force needed to keep a 0.1 kg basketball moving at a constant speed of 6 m/s on friction less ice is ____ Newtons

1 answer:

7 0

Basketball has a mass of 0.1kg
m = 0.1 kg
The basket ball is moving at constant speed, this shows that it is not accelerating. So, acceleration is zero
a = 0m/s²
The constant speed is 6m/s
v = 6m/s
So, force to keep it moving with this constant speed can be calculated using Newton second law of motion
F = ma
F = m × 0
F = 0N
So, since the basket ball is moving at constant speed, then, the force need to keep the ball moving is 0N.

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The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation

Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

Sample size: n = 20
Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}$

This gives

$P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}$

$P(x = 11) = 0.0011$

Express as percentage

$P(x = 11) = 0.11\%$

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}$

This gives

$P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0$

$P(x = 20) = 0.0388$

Express as percentage

$P(x = 20) = 3.88\%$

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

$\mu = np$

So, we have:

$\mu = 20 \times 85\%$

$\mu = 17$

The standard deviation is calculated as:

$\sigma = np(1 - p)$

So, we have:

$\sigma = 20 \times 85\% \times (1 - 85\%)$

$\sigma = 20 \times 0.85 \times 0.15$

$\sigma = 2.55$

Hence, the mean and the standard deviation are 17 and 2.55, respectively.

Read more about probabilities at:

brainly.com/question/15246027

8 0

3 years ago

Homeowners insurance covers loss of a home caused by which of the following two factors?

denis23 [38]

The first and the third option are correct. if you fail to do the second and last they will take away your house lol

7 0

3 years ago

Read 2 more answers

The legs of an isosceles right triangle are 5 inches long. What is the length of the hypotenuse of the triangle to the nearest i

In-s [12.5K]

The legs are 5 inches long.

Use the Pythagorean theorem:
$5^2+5^2=c^2 \\
25+25=c^2 \\
50=c^2 \\
c=\sqrt{50} \\
c=\sqrt{25 \times 2} \\
c=5 \sqrt{2} \\
c \approx 7$

The length of the hypotenuse of the triangle is approximately 7 inches long.

6 0

4 years ago

Read 2 more answers

Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

</span> $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

4 years ago

Simplify and show work <br><br> 5x - (6 - x)

Scilla [17]

Answer:

6x-6

Step-by-step explanation:

5x-(6-x)

First you distribute the negative to (6-x) which makes -6+x, then you just subtract that from 5x which makes 5x-6+x then you just simplify into 6x-6.

4 0

3 years ago