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Sedaia [141]
3 years ago
10

I need help trying to answer sin–1 2/3

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
6 0

Answer:

41.81 is the answer rounded to the nearest hundredth.

Step-by-step explanation:

You need to insert inverse sin into your calculator and then put parentheses 2/3. (2/3)

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An elementary school teacher must purchase 4.51 cups of flour per student for a class project. If she has 38 students, use estim
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She needs 171.38 cups of flour for all of her students.

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The value of a plot of land is S18 000.00.
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$126

Step-by-step explanation:

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What statements must be true of an equation before you can use quadratic formula?
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4 years ago
Find all solutions in the interval from [0,2pi)<br> 2cos(3x)= -sqrt{2}
algol [13]

Solutions of 2cos(3x)= -\sqrt{2} in the interval from [0,2pi) is x =\frac{\pi}{12}  and x = \frac{23\pi}{12} .

<u>Step-by-step explanation:</u>

Find all solutions in the interval from [0,2pi)

2cos(3x)= -\sqrt{2}

⇒ 2cos(3x)= -\sqrt{2}

⇒ \frac{2cos(3x)}{2}= \frac{-\sqrt{2}}{2}

⇒ cos3x= \frac{-\sqrt{2}(\sqrt{2})}{2{\sqrt{2}}}

⇒ cos3x= \frac{-2}{2{\sqrt{2}}}

⇒ cos3x= \frac{-1}{{\sqrt{2}}}

⇒ cos^{-1}(cos3x)= cos^{-1}(\frac{-1}{{\sqrt{2}}})

⇒ 3x=\pm \frac{\pi}{4}

⇒ x=\pm \frac{\pi}{12}

Cosine General solution is :

x = \pm cos^{-1}(y)+ 2k\pi

⇒ x = \pm \frac{\pi}{12}+ 2k\pi , k is any integer .

At k=0,

⇒ x =\frac{\pi}{12} ,

At k=1,

⇒ x = - \frac{\pi}{12}+ 2\pi

⇒ x = \frac{23\pi}{12}

Therefore , Solutions of 2cos(3x)= -\sqrt{2} in the interval from [0,2pi) is x =\frac{\pi}{12}  and x = \frac{23\pi}{12} .

5 0
3 years ago
A number of apples divided into 12 baskets
Temka [501]
You would represent the number of apples with the variable a.

So the equation for that word problem would be = a/12.

I hope you find this answer the most helpful! :)
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