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Salsk061 [2.6K]
2 years ago
14

Answer only one question​ No 1 only​

Mathematics
2 answers:
Svet_ta [14]2 years ago
4 0

-10369

too lazy but that's the exact value

Lemur [1.5K]2 years ago
4 0

Answer:

Step-by-step explanation:

(-2)³ *(-4)² * 3⁴ = (-8) * 16 * 81

                      = -10368

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The absolute value of any negative number is greater than zero True or False
Vaselesa [24]
The answer is true. Pretty darn sure
6 0
3 years ago
-4(w+1)=-24<br><br> what does w equal?
makvit [3.9K]

Answer:

w=5

Step-by-step explanation:

using the distributive property to simplify the equation

-4(w)+1(-4)=-24 so

-4w-4=-24 (adding 4 to both sides)

-4w==20 (divide by -4)

w=5

8 0
3 years ago
Read 2 more answers
Solve the following equation by completing the square. 3x^2-3x-5=13
mr Goodwill [35]

we'll start off by grouping some

\bf 3x^2-3x-5=13\implies (3x^2-3x)-5=13\implies 3(x^2-x)-5=13 \\\\\\ 3(x^2-x)=18\implies (x^2-x)=\cfrac{18}{3}\implies (x^2-x)=6\implies (x^2-x+~?^2)=6

so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

\bf \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2-\left[ \cfrac{1}{2} \right]^2 \right)=6\implies \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2 \right)-\left[ \cfrac{1}{2} \right]^2=6 \\\\\\ \left(x-\cfrac{1}{2} \right)^2=6+\cfrac{1}{4}\implies \left(x-\cfrac{1}{2} \right)^2=\cfrac{25}{4}\implies x-\cfrac{1}{2}=\sqrt{\cfrac{25}{4}} \\\\\\ x-\cfrac{1}{2}=\cfrac{\sqrt{25}}{\sqrt{4}}\implies x-\cfrac{1}{2}=\cfrac{5}{2}\implies x=\cfrac{5}{2}+\cfrac{1}{2}\implies x=\cfrac{6}{2}\implies \boxed{x=3}

6 0
3 years ago
Amanda needs to make a garden plot which has an area less than 18 sq. feet. The length should be 3 feet longer than the width. W
SCORPION-xisa [38]

Answer:

<em>Any width less than 3 feet</em>

Step-by-step explanation:

<u>Inequalities</u>

The garden plot will have an area of less than 18 square feet. If L is the length of the garden plot and W is the width, the area is calculated by:

A = L.W

The first condition can be written as follows:

LW < 18

The length should be 3 feet longer than the width, thus:

L = W + 3

Substituting in the inequality:

(W + 3)W < 18

Operating and rearranging:

W^2 + 3W - 18 < 0

Factoring:

(W-3)(W+6)<0

Since W must be positive, the only restriction comes from:

W - 3 < 0

Or, equivalently:

W < 3

Since:

L = W + 3

W = L - 3

This means:

L - 3 < 3

L < 6

The width should be less than 3 feet and therefore the length will be less than 6 feet.

If the measures are whole numbers, the possible dimensions of the garden plot are:

W = 1 ft, L = 4 ft

W = 2 ft, L = 5 ft

Another solution would be (for non-integer numbers):

W = 2.5 ft, L = 5.5 ft

There are infinitely many possible combinations for W and L as real numbers.

6 0
3 years ago
Identify the initial value in each formula below, and state whether the formula models exponential growth or
Hitman42 [59]

Answer: Hello mate!

the equation is written is:

f(t) = 2 / 3 (3)t

And is hard to work with this, but let's try:

I will interpret this function in two ways:

f(t) = (2/3^(3t)) in this case, the exponential part is in the denominator, so when t increases, the denominator also increases, if the denominator increases, the value of the function decreases, then, in this case, we have an exponential decay.

second case:

f(t) = (2/3)^(3t) the case is similar.

we know that 2/3 < 1

now, (2/3)^3t = (2^3t/3^3t)

3 is a number bigger than 2, then 3^3t > 2^3t, meaning that when t increases, bot denominator, and numerator increases, but the denominator increases faster, this means that we still have an exponential decay.

5 0
3 years ago
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