Applying Newton's Second Law, it is found that the force, in Newtons, is given by:
![F = 10[v(21) - v(16)]](https://tex.z-dn.net/?f=F%20%3D%2010%5Bv%2821%29%20-%20v%2816%29%5D)
Newton's Second Law states that Force, in Newtons, is <u>mass times acceleration</u>, that is:

In this problem, mass of 50 kg, thus 
Acceleration is <u>change in velocity divided by change in time</u>, that is:

In this problem, we don't know the velocities, but know that time is from 16s to 21s, thus:


Thus, the force is given by:


![F = 50\frac{[v(21) - v(16)]}{5}](https://tex.z-dn.net/?f=F%20%3D%2050%5Cfrac%7B%5Bv%2821%29%20-%20v%2816%29%5D%7D%7B5%7D)
![F = 10[v(21) - v(16)]](https://tex.z-dn.net/?f=F%20%3D%2010%5Bv%2821%29%20-%20v%2816%29%5D)
A similar problem is given at brainly.com/question/18801986
Answer:
I think it is 12 and 1/3 and 121 over 3
Answer:
The answer is √5
Step-by-step explanation:
That's it
Let us consider the initial position of train A,
. This implies that
.
Moreover, we have

This implies that the two equations are

The two trains meet if and only if their positions are the same, at the same time:

So, the two trains meet after 2 hours.
Answer:1110
Step-by-step explanation:Move over the decimal point to the right of .01 until it becomes a whole number (1). Then move over the decimal point of 11.1 the same amount of times you did for .01. This should get you 1110/1 which is 1110.