Question

Please help, last unit of algebra 2, thankyou!!!!!!!!!!!!​

Answer 1

Answer:

$\cot \theta = \frac{8}{15} \\\\\sec \theta = \frac{17}{8} \\\\\csc \theta = \frac{17}{15}$

Step-by-step explanation:

$\huge \tan \theta = \frac{15}{8} ...(given) \\ \\ \huge \because \: \cot \theta = \frac{1}{ \tan \theta} \\ \\ \huge \therefore \: \cot \theta = \frac{1}{ \frac{18}{8} } \\ \\ \huge \therefore \: \cot \theta = \frac{8}{15} \\ \\ also \\ \huge \sec \theta = \frac{17}{8}$