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3 years ago

15

A ball is dropped from rest from a tower and strikes the ground 125meters below. Approximately how many seconds does it take for

the ball to strike the ground after being dropped? Neglect air resistance.

1 answer:

kogti [31]3 years ago

4 0

Oh ok thanks i i miss me calf and she is going on the ground

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When a baseball is hit, it travels around 65 mps (meters per second). the mass of the baseball is 0.145 kg. what is the kinetic

nika2105 [10]

Answer:

306J

Explanation:

The formula for kinetic energy is given as ½mv².

Using this, we get our answer by substituting the values into the formula.

½ × 0.145kg × 65m/s

= 306.31J

can be rounded off to 306J

4 0

2 years ago

A movie star catches a paparazzi reporter snapping pictures of her at home and claims that he was trespassing. He, of course den

guajiro [1.7K]

Answer:

44.755 m

Explanation:

Given:

Height of the movie star, H = 1.75 m = 1750 mm

Height of the image, h = - 8.25 mm

Focal length of the camera = 210 mm

Let the distance of the object i.e the distance between camera and the movie star be 'u'

and

distance between the camera focus and image be 'v'

thus,

magnification, m = $\frac{\textup{h}}{\textup{H}}$

also,

m = $\frac{\textup{-v}}{\textup{u}}$

thus,

$\frac{\textup{-v}}{\textup{u}}=\frac{\textup{h}}{\textup{H}}$

or

$\frac{\textup{-v}}{\textup{u}}=\frac{\textup{-8.25}}{\textup{1750}}$

or

$\frac{\textup{1}}{\textup{v}}=-\frac{\textup{1750}}{\textup{-8.25}}\times\frac{1}{\textup{u}}$ ....................(1)

now, from the lens formula

$\frac{\textup{1}}{\textup{f}}=\frac{\textup{1}}{\textup{u}}+\frac{1}{\textup{v}}$

on substituting value from (1)

$\frac{\textup{1}}{\textup{210}}=\frac{\textup{1}}{\textup{u}}+-\frac{\textup{1750}}{\textup{-8.25}}\times\frac{1}{\textup{u}}$

or

$\frac{\textup{1}}{\textup{210}}=\frac{\textup{1}}{\textup{u}}(1 -\frac{\textup{1750}}{\textup{-8.25}})$

or

u = 210 × ( 1 + 212.12 )

or

u = 44755.45 mm

or

u = 44.755 m

6 0

4 years ago