Answer:
45 degrees
Explanation:
The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees.
To solve this exercise it is necessary to take into account the concepts related to Tensile Strength and Shear Strenght.
In Materials Mechanics, generally the bodies under certain loads are subject to both Tensile and shear strenghts.
By definition we know that the tensile strength is defined as
Where,
Tensile strength
F = Tensile Force
A = Cross-sectional Area
In the other hand we have that the shear strength is defined as
where,
Shear strength
Shear Force
Parallel Area
PART A) Replacing with our values in the equation of tensile strenght, then
Resolving for F,
PART B) We need here to apply the shear strength equation, then
In such a way that the material is more resistant to tensile strength than shear force.
Answer:
7. They arethe meter (m), the kilogram (kg), the second (s), the kelvin (K), the ampere (A), the mole (mol), and the candela (cd)
Explanation:
7. They arethe meter (m), the kilogram (kg), the second (s), the kelvin (K), the ampere (A), the mole (mol), and the candela (cd)
<h2>Greetings!</h2>
To find this value, you need to remember the speed formula:
3 = 6 / 2
Speed = distance ÷ time
Rearrange to make distance the subject:
Distance = speed * time
Simply plug these values into this:
5.6 * 8.25 = 46.2
<h3>So the player will travel 46.2 metres!</h3>
<h2>Hope this helps!</h2>
Answer:
T is less than or equal to 19 N
Explanation:
