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JulsSmile [24]
3 years ago
10

A 1.05m long rod of negligible weight is supported at its ends by wires A and B of equal length with diameter of B three times t

hat of A. If the Young’s modulus of wire A is 3.5 times that of B, compute the value of x that will produce (a) equal stress in A and B (b) equal strain in A and
Physics
1 answer:
SpyIntel [72]3 years ago
5 0
A+B+C+D+E+F+G+H+I+J+K+L+M+N+O+P
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386.5<br>- 129.18 what is it​
algol [13]

Answer:

257.32

Explanation:

I jus worked it out on paper. Brainliest please?

5 0
3 years ago
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A football wide receiver rushes 16 m straight down the playing field in 2.9 s (in the positive direction). He is then hit and pu
Bumek [7]

Answer:

a) v1 = 5.52m/s

b) v2 = -1.52m/s

c) v3 = 4.62m/s

d) vt = 3.85m/s

Explanation:

The velocity of the football wide receiver is his displacement per unit time.

Velocity v = (displacement d)/time t

v = d/t .....1

For each of the cases, equation 1 would be used to calculate the velocity.

a) v1 = d1/t1

d1= 16m

t1 = 2.9s

v1 = 16m/2.9s

v1 = 5.52m/s

b) v2 = d2/t2

d2 = -2.5m

t2 = 1.65s

v2 = -2.5/1.65

v2 = -1.52m/s

c) v3 = d3/t3

d3 = 24m

t3 = 5.2s

v3 = 24/5.2

v3 = 4.62m/s

d) vt = dt/tt

dt = 16m - 2.5m + 24m = 37.5m

tt = 2.9 + 1.65 + 5.2 = 9.75s

vt = 37.5/9.75

vt = 3.85m/s

5 0
4 years ago
What potential difference is needed to give a helium nucleus (q=2e) 85.0 kev of kinetic energy?
Vilka [71]
The kinetic energy K given to the helium nucleus is equal to its potential energy, which is 
E=q \Delta V
where q=2e is the charge of the helium nucleus, and \Delta V is the potential difference applied to it.
Since we know the kinetic energy, we have
E=K=85~keV=q \Delta V
and from this we can find the potential difference:
\Delta V =  \frac{K}{q}= \frac{85~keV}{2e}=42.5~kV

6 0
3 years ago
You took a running leap off a high diving platform. You were running at 3.1 m/s and hit the water 2.4 seconds later. How high wa
rusak2 [61]

The distance you free-fall from rest is  D = (1/2) (g) (T²) <== memorize this

Height of the platform = (1/2) (9.8 m/s²) (2.4 sec)²

Height = (4.9 m/s²) (5.76 s²)

Height = (4.9/5.76) meters

Height = 28.2 meters (a VERY high platform ... about 93 ft off the water !)

Without air-resistance, your horizontal speed doesn't change.  It's constant.  Traveling 3.1 m/s for 2.4 sec, you cover (3.1 m/s x 2/4 s) = 7.4 m horizontally.

7 0
4 years ago
A machine can never be 100% efficient because some work is always lost due to what?
katrin [286]

A machine can never be 100% efficient because some work is always lost due to the lack of materials or equipment that would convert work by 100%. It follows the second law of entropy. The ideal engine is known as Carnot’s engine having a 100% efficiency. So far, no engine has ever gotten to 100%.

8 0
4 years ago
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