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Arturiano [62]
4 years ago
6

Eating an orange enables a person to perform about 3.5x10^4 J of work. To what height does eating and orange enable a 55kg woman

to climb?
Physics
2 answers:
xenn [34]4 years ago
4 0

Answer:

65 m

Explanation: hope this helps!

crimeas [40]4 years ago
3 0
Joules is a unit for work which may decomposed into N.m. Work is a quantity which is a product of force (in this case, the woman's weight) and the distance she has traveled. 
 
                                    W = F x d      ;    d = W / F

Substituting the given, 
  
                             d = (3.5 x 10^4 J) / (55 kg x 9.8 m/s²) = 64.94 m

Thus, the woman can climb up to 64.94 meters. 

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 (a) How long can you rapidly climb stairs (116/min) on the 166.0 kcal of energy in a 200g apple? (b) How many flights is this
adoni [48]

Answer:

a) It will take you 16.94 min to climb the stairs.

b) The numbers of flights are 123 flights.

Explanation:

a) Let the energy consumption while climbing the stairs be 685 W in kcal/min is given by:

rate of energy consumption = (685 W)×[(0.01433kcal/min)/1 W]

                                               = 9.81605 kcal/min

the time it takes to climb the stairs is given by:

t = E/P

 = (166.0 kcal)/(9.8 kcal/min)

 = 16.94 min

Therefore, it will take you 16.94 min to climb the stairs.

b) Given t is the time it takes to climb stairs and N is the number of stairs to climb per min, then the number of stairs is:

n = t×N

  = (16.94)×(116)

  = 1965 stairs

given the number of stairs each flight as N1, then the number of flights is given by:

flights = n/N1

          = (1965)/(16)

          = 123 flights

Therefore, the numbers of flights are 123 flights.

7 0
4 years ago
A 2.1 ✕ 103-kg car starts from rest at the top of a 5.9-m-long driveway that is inclined at 19° with the horizontal. If an avera
Lina20 [59]

Answer:

3.9 m/s

Explanation:

We are given that

Mass of car,m=2.1\times 10^3 kg

Initial velocity,u=0

Distance,s=5.9 m

\theta=19^{\circ}

Average friction force,f=4.0\times 10^3 N

We have to find the speed of the car at the bottom of the driveway.

Net force,F_{net}=mgsin\theta-f=2.1\times 10^3\times 9.8sin19-4.0\times 10^3

Where g=9.8 m/s^2

Acceleration,a=\frac{F_{net}}{m}=\frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}

v=\sqrt{2as}

v=\sqrt{2\times \frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}\times 5.9}

v=3.9 m/s

7 0
3 years ago
Please help me with this question
valkas [14]

Answer: m∠P ≈ 46,42°

because using the law of sines in ΔPQR

=> sin 75°/ 4 = sin P/3

so ur friend is wrong due to confusion between edges

+) we have: sin 75°/4 = sin P/3

=> sin P = sin 75°/4 . 3 = (3√6 + 3√2)/16

=> m∠P ≈ 46,42°

Explanation:

4 0
3 years ago
Scientific endeavor is sometimes accompanied by negative tradeoffs.<br> true or false???????????? :0
Ilia_Sergeevich [38]


i think true 
false is false

5 0
3 years ago
From the top of a cliff, a person uses a slingshot to fire a pebble straight downward, which is the negative direction. The init
In-s [12.5K]

Answer:

a) the acceleration is -9.8 m/s^2 (gravity's acceleration), the magnitude is 9.8 m/s^2 and the direction is downwards.

The pebble is not decelerating since the magnitude of it's speed is increasing, even if it is on a negative direction.

b) after 0.5 s the pebble is 5.725 meters down. (or -5.725m from it's initial position.)

Explanation:

a) the acceleration is given only by gravity, it's the only force acting on the pebble, the slingshot only gives the pebble an initial speed.

b) To calculate the position we use the equation

y0 + v0·t + ½·g·t² = yf

replacing:

0 + (-9.0m/s) * 0.5s + 1/2 (-9.8)*0.5² = yf

-5.725 = yf

7 0
4 years ago
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