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Arturiano [62]
3 years ago
6

Eating an orange enables a person to perform about 3.5x10^4 J of work. To what height does eating and orange enable a 55kg woman

to climb?
Physics
2 answers:
xenn [34]3 years ago
4 0

Answer:

65 m

Explanation: hope this helps!

crimeas [40]3 years ago
3 0
Joules is a unit for work which may decomposed into N.m. Work is a quantity which is a product of force (in this case, the woman's weight) and the distance she has traveled. 
 
                                    W = F x d      ;    d = W / F

Substituting the given, 
  
                             d = (3.5 x 10^4 J) / (55 kg x 9.8 m/s²) = 64.94 m

Thus, the woman can climb up to 64.94 meters. 

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An object is placed in front of a diverging lens, such that the object-to-image distance is 71 cm.
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Explanation:

Given that,

Object-to-image distance d= 71 cm

Image distance = 26 cm

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u -v= d

u=71+26=97\ cm

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\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

put the value into the formula

\dfrac{1}{f}=\dfrac{1}{-26}+\dfrac{1}{97}

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(B). Given that,

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Focal length = 29 cm

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Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

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3 years ago
A 100kg crate slides along a floor with a starting velocity of 21ms If the force due to friction is 8N how long will it take for
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A 100kg crate slides along a floor with a starting velocity of 21 m/s. If the force due to friction is 8N, then, it will take 262.5 s for the box to come to rest.

We'll begin by calculating the declaration of the box. This can be obtained as follow:

Force (F) = –8 N (opposition)

Mass (m) = 100 Kg

<h3>Deceleration (a) =? </h3>

<h3>F = ma</h3>

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Divide both side by 1000

a = \frac{-8}{100}

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Therefore, the deceleration of the box is –0.08 ms¯²

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Deceleration (a) = –0.08 ms¯²

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<h3>Time (t) =.? </h3>

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Therefore, it will take 262.5 s for the box to come to rest.

Learn more: brainly.com/question/14446351

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