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JulsSmile [24]
3 years ago
12

If the zeros of a quadratic functions are -2 and 4, which graph could represent the function?

Mathematics
1 answer:
anygoal [31]3 years ago
4 0

Answer:

The Graph having the X-intercepts of (-2,0) and (4,0)

Step-by-step explanation:

The zeroes of the function is the X-intercept.

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What is 28.6 rounded to the nearest tenth ?
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Answer: 28.6

Step-by-step explanation:

To round 28.6 to the nearest tenth consider the hundredths’ value of 28.6, which is 0 and equal or more than 5. Therefore, the tenths value of 28.6 increases by 1 to 7.28.6 rounded to the nearest tenth = 28.6 hope that helps

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Help me please , ps have a good day :))
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the second one (Diego)

Step-by-step explanation:

7a-3a

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Write the parametric equations in the given Cartesian form. x = 3t-t³, y=2-3t​
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2 years ago
The valve was tested on 270 engines and the mean pressure was 6.6 lbs/square inch. Assume the variance is known to be 0.49. If t
BlackZzzverrR [31]

Answer:

z=\frac{6.6-6.5}{\frac{0.7}{\sqrt{270}}}=2.347      

The p value for this case would be given by"

p_v =2*P(z>2.347)=0.0189  

For this case since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean is significantly different from 6.5 lbs/square inch at 10% of significance. So then there is not enough evidence to conclude that the valve does not perform to the specifications

Step-by-step explanation:

Information given

\bar X=6.6 represent the sample mean

s=\sqrt{0.49}= 0.7 represent the population deviation

n=270 sample size      

\mu_o =6.5 represent the value that we want to test    

\alpha=0.1 represent the significance level

z would represent the statistic

p_v represent the p value for the test

Hypothesis to verify

We want to verify if the true mean for this case is equal to 6.5 lbs/square inch or not , the system of hypothesis would be:      

Null hypothesis:\mu= 6.5      

Alternative hypothesis:\mu \neq 6.5      

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

And replacing we got:

z=\frac{6.6-6.5}{\frac{0.7}{\sqrt{270}}}=2.347      

The p value for this case would be given by"

p_v =2*P(z>2.347)=0.0189  

For this case since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean is significantly different from 6.5 lbs/square inch at 10% of significance. So then there is not enough evidence to conclude that the valve does not perform to the specifications

8 0
4 years ago
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