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2 years ago

If the zeros of a quadratic functions are -2 and 4, which graph could represent the function?

Mathematics

1 answer:

anygoal [31]2 years ago

4 0

Answer:

The Graph having the X-intercepts of (-2,0) and (4,0)

Step-by-step explanation:

The zeroes of the function is the X-intercept.

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So difficult!!! Someone help

Naya [18.7K]

When two lines cross like this, sum of measures of opposite angles is 180.
this means that:
measure angle AEC + measure angle BED = 180
4x-40 + x+50 = 180
5x +10 = 180
5x = 170
x = 34
therefore:
measure angle AEC = 4x-40 = 4(34)-40 = 96
measure angle BED = x+50 = 34+50 = 84

5 0

3 years ago

The label on the car's antifreeze container claims to protect the car between −40°C and 125°C. To covert Celsius temperature to

Solnce55 [7]

Answer:

see below

Step-by-step explanation:

The label on the car's antifreeze container claims to protect the car between -40°C and 125°C.

So inequality which models this situation will be -40°C < T < 125°C

Now we have to show this inequality in Fahrenheit temperature with the help of $C=\frac{5}{9} (F-32)$

So the compound inequality in Fahrenheit temperature will be

$-40 < \frac{5}{9} (F-32) < 125$

7 0

2 years ago

There are $1.95 worth of nickels and quarters in a piggy bank there are three more nickels than quarters how many of each are in

Gennadij [26K]

Answer:

6 quarters and 9 nickels

Step-by-step explanation:

6 quarters is equal to $1.50. 6 nickels is equal to $0.30. Those together equal $1.80, then add the three nickels bringing your total to $1.95.

3 0

2 years ago

Read 2 more answers

Write the equation of the line in slope-intercept form of the statement

Law Incorporation [45]

Answer:

Y= -2x +40

Step-by-step explanation:

6 0

2 years ago

What equation in slope intercept form represents the line that passes through the two points 2,5 (9,2

vredina [299]

$General\ equation\ for\ line\ in\ slope\ intercept\ form:\\\\y=ax+b\\\\To\ find\ a\ and\ b\ substitude\ points\ (2,5),\ (9,2)\ into\ equation\\\\ \left \{ {{5=2a+b} \atop {2=9a+b}} \right. \\\\b=5-2a\ \ \ \ \ \ \ \ \ \ \ \ |from\ first\ equation\\\\2=9a+5-2a\ \ \ \ \ |substituting\ to\ the\ second\\2-5=7a\\7a=-3\\a=-\frac{3}{7}\\\\b=5-2\cdot(-\frac{3}{7})\\b=5+\frac{6}{7}=5\frac{6}{7}\\\\y=-\frac{3}{7}+5\frac{6}{7}$

8 0

3 years ago