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Goryan [66]
3 years ago
6

Can u plsss help me out with this thanks

Mathematics
2 answers:
alex41 [277]3 years ago
8 0

Number 3 is x=3 Number 5 is x=-1 Number 7 is x=9 Number 9 is x=10

grigory [225]3 years ago
4 0
You already have the answers but what you do is distribute if you need help with that just comment and Ill help you with it <3
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The graph of f(x) = |x| is transformed to g(x) = |x + 1| – 7. On which interval is the function decreasing?
timofeeve [1]

Answer:

g is decreasing for all x less than or equal to -1

Step-by-step explanation:

The graph of the function y = |x| looks like a "vee."

g(x) = |x + 1| - 7 moves that graph 1 unit to the <u>left</u><em> </em>(I know, it looks backwards!) and down 7 units. See attached image.

Function g(x) is decreasing for all x \le -1.

5 0
3 years ago
Read 2 more answers
A batman costume costs $20. A harlequin costume costs twice as much as the batman costume. How much does a harlequin costume cos
Gnoma [55]

Answer:the harleyquin costume would cost 40 $

Step-by-step explanation: as given the batman costume costs 20$. so 20 times 2 equals 40$.

20*2= 40$

6 0
3 years ago
Read 2 more answers
At Ajax Spring Water, a half-liter bottle of soft drink is supposed to contain a mean of 519 ml. The filling process follows a n
k0ka [10]

Answer:

1) The normal distribution should be used for the sample mean because the population distribution is known to be normal (answer b).

2) C. H0: mu = 519, H_1: mu not equal to 519, reject if z> 1.96 or z< -1.96.

3) Yes. There is enough evidence to support the claim that the true mean is not 519 ml.

Step-by-step explanation:

1) When the population follows a normal distribution, it is correct to assume a normal distribution for the sample mean.

2) As it is a two-tailed decision rule, we are interested in detecting a significant difference below and above the mean. This is why we use the unequal sign in the alternative hypothesis.

The null hypothesis state that there is not significant difference from 519.

The critical value for a significance level of 5% is z=1.96.

H_0: \mu=519\\\\H_a:\mu\neq 519

3) The claim is that the true mean is not 519 ml.

Then, the null and alternative hypothesis are:

H_0: \mu=519\\\\H_a:\mu\neq 519

The significance level is 0.05.

The sample has a size n=16.

The sample mean is M=522.

The standard deviation of the population is known and has a value of σ=6.

We can calculate the standard error as:

\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{16}}=1.5

Then, we can calculate the z-statistic as:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{522-519}{1.5}=\dfrac{3}{1.5}=2

This test is a two-tailed test, so the P-value for this test is calculated as:

\text{P-value}=2\cdot P(z>2)=0.046

As the P-value (0.046) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the true mean is not 519 ml.

7 0
3 years ago
Please help! Will mark brainliest!
zhuklara [117]

Answer:

5/2

Step-by-step explanation:

Move the 5^-3 to the denominator and add the exponents of like coefficents

6 0
3 years ago
Marking brainliest
Ede4ka [16]

36%

Hope this is right im only 11  :)

8 0
4 years ago
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