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son4ous [18]
3 years ago
12

A point on a string undergoes simple harmonic motion as a sinusoidal wave passes. When a sinusoidal wave with speed 24 m/s, wave

length 30 cm, and amplitude of 1.0 cm passes, what is the maximum speed of a point on the string?
Physics
1 answer:
Anit [1.1K]3 years ago
6 0

Answer:

5.03 m/s

Explanation:

Give

Speed = v = 24m/s

Wavelength = λ = 30cm = 0.3m

Amplitude = A = 1.0cm = 0.01m

The velocity of a point in Simple Harmonic Motion

at any time t is given by the following formula

v = ωA cos ωt

The value is the Maximum when cosωt.

The maximum value of cosωt. is 1.

Hence the maximum velocity is ωA

Velocity of the wave v=n λ

n = v/ λ = 24 /0.3 = 80

ω = 2πn = 2π*80 = 502.86 rad/s

Maximum velocity of the particle is

ωA = 502.86 * 0.01 = 5.03m/s

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Answer:

9375 N

Explanation:

From the question,

Centripetal force (F) = mv²/r.................. Equation 1

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Given: m = 900 kg, r = 600 m, v = 25 m/s

Substitute these values into equation 1

F = (900×25²)/600

F = 9375 N.

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Answer:

Please refer to the figure.

Explanation:

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The current density is constant for different parts of the wire. This idea is similar to that of the density of a glass of water is equal to the density of a whole bucket of water.

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