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Novosadov [1.4K]
3 years ago
9

A boy steps off the end of a 3.00 m high diving board and drops to the water below. Using 9.8 m/s2 as acceleration due to earth'

s gravity, how many seconds does it take for him to reach the water? Only enter the number, not the units.
Physics
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

t = 0.78 s

Explanation:

Given that,

The height of a diving board, h = 3 m

We need to find the time it take for him to reach the water. Let the time is t./

Using second equation of motion as follows :

h=ut+\dfrac{1}{2}at^2

u is initial velocity, u = 0 and a = g

So,

h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\cdot3}{9.8}}\\\\t=0.78\ s

So, it will take 0.78 seconds to reach the water.

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1.11×10⁸  Electrons.

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Determine the magnitude of the resultant force and its direction using both the parallelogram and Cartesian vector notation meth
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   F = 1494.52 N,   θ = 44º

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The attachment shows this roughly.

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           cos θ = x / R

            y = R sin θ

            x = R cos θ

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            sin 50 = \frac{F_{1y} }{F_1}

            cos 50 = \frac{F_{1x} }{F_1}

            F_{1y} = F₁ sin 50

            F₁ₓ = F₁ cos 50

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            Fₓ = 385.67 + 689.44

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            F = Fₓ² + F_{y}^2

            F = √(1075.11² + 1038.14²)

            F = 1494.52 N

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            tan θ = F_y / Fₓ

            θ = tan⁻¹ (F_y / Fₓ)

            θ = tan⁻¹ (1038.14 / 1075.11)

            θ = 44º

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