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levacccp [35]
3 years ago
13

A spacecraft flies away from the earth with a speed of 4.80×106m/s relative to the earth and then returns at the same speed. The

spacecraft carries an atomic clock that has been carefully synchronized with an identical clock that remains at rest on earth. The spacecraft returns to its starting point 365 days (1 year) later, as measured by the clock that remained on earth. What is the difference in elapsed time on the two clocks,measured in hour?
Physics
1 answer:
marta [7]3 years ago
3 0

Answer:

1.1215 h

Explanation:

Δt=Δt_o/√(1-u^2/c^2)

(Δt° is the proper time in the rest frame,

Δt is the time intent measured in the second frame of reference u is the speed of the second frame with respect to the rest frame c is the speed of light )  

a) the proper time is the time on spacecraft (rest frame);

Δt = 365 days = 8760 h  

Δt=Δt_o/√(1-u^2/c^2)= 8761.1215 h

the difference = 8761.1215 h — 8760 h   = 1.1215 h

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A spy satellite uses a telescope with a 1.7-m-diameter mirror. It orbits the earth at a height of 180 km.
WINSTONCH [101]

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wavelength λ = 500 nm = 5 × 10⁻⁹ m

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sin∅= 1.22 λ / d

sin∅ = (1.22 × 5 × 10⁻⁹) / 1.7

 sin∅ = 3.588 × 10⁻⁷

we know that;

 sin∅  = object separation / distance from telescope

object separation =   sin∅ × distance from telescope

object separation = 3.588 × 10⁻⁷  × 180 × 10³

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5 0
3 years ago
A box is held at rest by two ropes that form 30° angles with the vertical. The tension T in either rope is 42 N. What is the wei
iragen [17]
<h3><u>Answer;</u></h3>

= 73 N

<h3><u>Explanation</u>;</h3>

Using the formula

2 T cos(30°) = w

Where; T is the tension on each string, while w is the weight of the box given by mg

Therefore;

W = 2Tcos 30°

    = 2 × 42 cos 30°

    = 84 cos 30°

    = 72.74

<u>   ≈ 73 N</u>

7 0
3 years ago
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