Answer:
The correct answer is-
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
2. Two genes, with a dominant allele at either or both loci.
Explanation:
The given information gives THE following data:
Dominant: Lancerate leaves - AABB
Recessive: normal leaves - aabb
F1 has - all Lacerated leaves - AaBb
F2 by selfing F1:
AB Ab aB ab
AB AABB AABb AaBB AaBb
Ab AABb AAbb AaBb Aabb
aB AaBB AaBb aaBB aaBb
ab AaBb Aabb aaBb aabb
Here, 15/16 = lacerate which is 0.94 which is equal to the value of lacerate given in the question - 249/265 = 0.94
And normal 1/16 = 0.062 is almost same as 16/265 = 0.060
Thus, the genotypes of -
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
A 100-pound bag of makes 345 pounds of nitrogen with hydro
Answer: The correct answer is option B) a scar and wolf's social status.
The acquired traits can be defined as the traits, which are only influenced by the environment of the organism. The acquired trait cannot be passed down to the offspring, as they are not genetically determined. A scar and the social status of any organism is dependent on the behavior of the organism to the environment, no genes code for both of these characters. So, scars and Wolf's social status is an acquired trait.
Explanation:
The question is asking to state the end result of Eukaryotic cell cycle, base on my research and further investigation, I would say that the correct answer would be that there is No parent cells and two daughter cells. I hope you are satisfied with my answer and feel free to ask for more
Gravity is pulling her towards the ground but also forward as the child is on a slope. Friction is pulling against the child as the slide pulls against her.
