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aniked [119]
3 years ago
14

Name the line segments

Mathematics
1 answer:
ratelena [41]3 years ago
6 0

Answer:

EF, FG, GH, EG, FH, EH

Step-by-step explanation:

These are all the ones under def. line segment.

See the attachment. It will be helpful.

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It is 0.385 as a decimal
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•) Find the sum.<br> -3 1/3 + (-1 2/3)
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Find the measure of the remote exterior angle. m∠x=(198−5n)°m∠y=(5n+37)°m∠z=(n+7)°
MrMuchimi

The value of the angle ∠x will be ∠x = 128°. Then the correct option is C.

<h3>What is the triangle?</h3>

A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.

The triangle is given below.

The sum of the two interior angle is equal to the third exterior angle.

m∠x = (198 − 5n)°

m∠y = (5n + 37)°

m∠z = (n + 7)°

We know that

∠x = ∠y + ∠z

198 - 5n = 5n + 37 + n + 7

       11n = 154

          n = 14

Then the value of the angle ∠x will be

∠x = 198 – 5 × 14

∠x = 128°

Then the correct option is C.

The complete question is given below.

More about the triangle link is given below.

brainly.com/question/25813512

#SPJ1

5 0
2 years ago
Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth
pav-90 [236]

Answer:

\sqrt{13} units

Step-by-step explanation:

The distance formula is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where d is the distance between points (x_1,y_1) and (x_2,y_2). Let (x_1,y_1)\rightarrow(5,1) and (x_2,y_2)\rightarrow(3,4), thus:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(3-5)^2+(4-1)^2}\\\\d=\sqrt{(-2)^2+(3)^2}\\\\d=\sqrt{4+9}\\\\d=\sqrt{13}

Therefore, the distance between points P(5,1) and Q(3,4) is \sqrt{13} units.

8 0
2 years ago
Six times the product of eleven and two
Pie

11x2=22

22x6=132

I believe the answer is 132

8 0
3 years ago
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