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Ainat [17]
3 years ago
6

The calorie count of a serving of food can be computed based on its composition of​ carbohydrate, fat, and protein. The calorie

count C for a serving of food can be computed using the formula Upper C equals 4 h plus 9 f plus 4 p​, where h is the number of grams of carbohydrate contained in the​ serving, f is the number of grams of fat contained in the​ serving, and p is the number of grams of protein contained in the serving. A serving of a certain type of nut contains 15 grams of​ fat, 6 grams of​ carbohydrate, and 5 grams of protein. How many calories are in this serving of​nuts?
Mathematics
2 answers:
earnstyle [38]3 years ago
8 0

C=4h+9f+4p

→4(6)+9(15)+4(5)

→24+135+20

→54+135

→189 calories

<h2><u>Mark as Brainliest</u></h2>
Mkey [24]3 years ago
5 0

Answer: The serving of nuts would contain 179 calories

Step-by-step explanation:

The calorie count C for a serving of food can be computed using the formula,

C = 4h + 9f + 4p

Where

h is the number of grams of carbohydrate contained in the​ serving,

f is the number of grams of fat contained in the​ serving, and

p is the number of grams of protein contained in the serving.

A serving of a certain type of nut contains 15 grams of​ fat, 6 grams of​ carbohydrate, and 5 grams of protein. Therefore, the number of calories in this serving of nuts would be

C = 4 × 6 + 9 × 15 + 4 × 5

C = 24 + 135 + 20 = 179

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If 5y = 6x + 16 and 9x = 7y-20, what is the value of 3x - 2y?
Law Incorporation [45]

The value of 3x-2y is -4. From the equation 5y=6x=16 and 9x=7y-20 the values of (x,y) is (4,8).

Step-by-step explanation:

        The given equations are,

                 5y=6x+16.......................(1)

                 9x=7y-20......................(2)

                3x-2y...............................(3)

Step:1

    Modify the equations (1) and (2) in (x+y=constant) format,

                6x-5y=-16.....................(4)

                9x-7y=-20....................(5)

Step:2

     Equation (4) is multiplied by 7     ( ∵ 7×Eqn(4))

                42x-35y=-112..............(6)

Step:3

     Equation (5) is multiplied by 5     (∵ 5×Eqn(5))

               45x-35y=-100.............(7)

Step:4

    Subtracting Equation (6) and (7)

               42x-35y=-112

              45x-35y=-100

    ( - )

     (42x-45x)+(35y-35y)=(100-112)

     (-3x)+(0)=(-12)

    x=4

Step:5

    Substitute X value in Equation (1),

             5y=6x+16...................(1)

     where, x=4,

             5y= (6×4)+16

             5y=40

            y= 8

Step: 6

      Check for solution, substitute x and y values in equation (2).

                9x=7y-20.......................(2)

               (9×4)=(7×8)-20

              36=36

Step:7

      From given, 3x-2y

      where, X=4 and y=8

              3x-2y = (3×4)-(2×8)

                        = 12-16

            3x-2y = -4

Result:

      The value for 3x-2y is -4. The values of (x,y) are (4,8).

   

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