The shorter side of the triangle is 18 cm and each of the longer sides are 54 cm
<u>Solution:</u>
Given that triangle has perimeter of 126 cm
Let the length of the shorter side of the triangle be "a"
The 2 longer sides are 3 times as long as the shortest side
So length of 2 longer sides = 3(length of the shorter side)
length of 2 longer sides = 3a
<em><u>The perimeter of triangle is given as:</u></em>
perimeter of triangle = length of the shorter side + length of 2 longer sides
perimeter of triangle = a + 3a + 3a
126 = a + 3a + 3a
7a = 126
a = 18
So length of shorter side = 18 cm
length of 2 longer sides are each = 3a = 3(18) = 54 cm
Thus, the shorter side of the triangle is 18 cm and each of the longer sides is 54 cm
Answer:
m⊥n
Step-by-step explanation:
the answer is n⊥m
Combine like terms
move the like terms together (x^2 with x^2, x with x, number wiht numbers)
4x^2-2x^2-5x+x+4+8
2x^2-4x+12
an equation is undefined, when its denominator is 0, or turns to 0, because we can't divide anything by 0.
so let's simply set the denominator of this one = 0.
![\bf x^2-7x+10=0\implies (x-2)(x-5)=0\implies x= \begin{cases} 2\\ 5 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(2)^2-9}{(2)^2-7(2)+10}\implies \cfrac{-5}{-10+10}\implies \cfrac{-5}{0}\leftarrow und efined \\\\\\ \cfrac{(5)^2-9}{(5)^2-7(5)+10}\implies \cfrac{16}{-10+10}\implies \cfrac{16}{0}\leftarrow und efined](https://tex.z-dn.net/?f=%5Cbf%20x%5E2-7x%2B10%3D0%5Cimplies%20%28x-2%29%28x-5%29%3D0%5Cimplies%20x%3D%20%5Cbegin%7Bcases%7D%202%5C%5C%205%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B%282%29%5E2-9%7D%7B%282%29%5E2-7%282%29%2B10%7D%5Cimplies%20%5Ccfrac%7B-5%7D%7B-10%2B10%7D%5Cimplies%20%5Ccfrac%7B-5%7D%7B0%7D%5Cleftarrow%20und%20efined%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B%285%29%5E2-9%7D%7B%285%29%5E2-7%285%29%2B10%7D%5Cimplies%20%5Ccfrac%7B16%7D%7B-10%2B10%7D%5Cimplies%20%5Ccfrac%7B16%7D%7B0%7D%5Cleftarrow%20und%20efined)
The length of the rectangle is 8 feet. X = 5
