All categories

3 years ago

What is 19 hundred thousandths in scientific notation

Mathematics

2 answers:

marissa [1.9K]3 years ago

5 0

.00019

move decimal to the right 4 places

hope this helps BRAINLIEST?

aniked [119]3 years ago

3 0

It is .00019

hope it helps!

You might be interested in

One equation in a system is y=3x+7. Which equation gives the system no solution

atroni [7]

Answer:

Step-by-step explanation:

Because I know how to do it

7 0

1 year ago

Read 2 more answers

Charles has six times as many action figures as ben together the action figures total more than 75 how many does each have

seropon [69]

Answer:

We have been given that Charles has six times as many action figures as Ben

Let Ben has x action figures

So according to question Charles will have 6x.

together the action figures total more than 75

$x+6x>75$

$7x>75$

$x>\frac{75}{7}$

So Ben will have more than $\frac{75}{7}$ action pictures.

And $6x>6\frac{75}{7}$

$6x>\frac{450}{7}$

Charles will have more than $\frac{450}{7}$ .

7 0

3 years ago

Write the following while number as it’s English word equivalent

ahrayia [7]

Answer:

eight hundred seventy-five thousand six hundred eighty-seven

<em>hope this helps :)</em>

8 0

2 years ago

Read 2 more answers

Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

7 0

3 years ago

Help please!!!!ASAP! Ill give brainliest! And 50pts!<br><br> What is the value of q?

fomenos

It is c hope this helps :)

4 0

2 years ago

Read 2 more answers