Answer:
A is the answer. Explanation is in the photo
Answer:
d.0.48
Explanation:
When a population is in Hardy Weinberg equilibrium the <u>genotypic </u>frequencies are:
freq (AA) = p²
freq (Aa) = 2pq
freq (aa) = q²
<em>p</em> is the frequency of the dominant <em>A</em> allele and <em>q</em> is the frequency of the recessive <em>a</em> allele.
In this population of 100 individuals, 84 martians have the dominant phenotype and 16 have the recessive phenotype.
Therefore:
q²=16/100
q² = 0.16
q=√0.16
q = 0.4
And p+q=1, so:
p = 1 - q
p = 1-0.4
p = 0.6
The frequency of heterozygotes is:
freq (Aa) = 2pq = 2 × 0.4 × 0.6
freq (Aa) = 0.48
Answer:
I believe the answer is D
Answer:
A.
Explanation:
Older fossils tend to lay in the lower levels of the ground. The further up the fossils are, the more likely you are to find something that looks like today. Think of it as stacking papers with different drawings on them from different ages. Oldest goes on the bottom, newest goes on the top. The older layer stands as more of a foundation point while newer layers are around where we are now.