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rosijanka [135]
3 years ago
13

In a class of 40 students, 30 read

Mathematics
1 answer:
DIA [1.3K]3 years ago
6 0
Ok so 24 of them and that would be ur answer
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3. Here is a diagram of a softball field:
Crank

a. Length of the fence around the field = perimeter of quarter circle = 892.7 ft.

b. The area of the outfield is about 39,584 sq. ft..

<h3>What is the Perimeter of a Quarter Circle?</h3>

Perimeter of circle = 2πr

Perimeter of a quarter circle = 2r + 1/4(2πr).

a. The length of the fence around the field = perimeter of the quarter circle fence

= 2r + 1/4(2πr).

r = 250 ft

Plug in the value

The length of the fence around the field = 2(250) + 1/4(2 × π × 250)

= 892.7 ft.

b. Size of the outfield = area of the full field (quarter circle) - area of the infield (cicle)

= 1/4(πR²) - πr²

R = radius of the full field = 250 ft

r = radius of the infield = 110/2 = 55 ft

Plug in the values

Size of the outfield = 1/4(π × 250²) - π × 55²

= 49,087 - 9,503

= 39,584 sq. ft.

Learn more about perimeter of quarter circle on:

brainly.com/question/15976233

4 0
2 years ago
The vertices of square WXYZ are W(-2, -1), X(-2,-5),Y(-6,-5), and Z(-6,-1) what is the perimeter and area of the square show you
labwork [276]
Line Segment WX=4
Line Segment XY=4 
Line Segment YZ=4
Line Segment ZW=4
4+4+4+4=16
The perimeter is 16 units.
7 0
3 years ago
Which best describes the triangle or triangles, if any, that can be formed with the sides measuring 60 centimeters, 100 centimet
Elis [28]
No triangle 60+40=100 which is the same as one side
6 0
3 years ago
Read 2 more answers
Given P(A) = 0.8, P(B) = 0.51 and P(ANB) = 0.468, find the value of
masha68 [24]

Answer:

Step-by-step explanation:

P(BA)=P(B)+P(A)-P(AnB)

= 0.51+0.8-0.468

=1.31-0.468

=0.842

P(BA) = 0.842

7 0
3 years ago
A principal of 2000 is invested at 3.25% interest, compounded annually. How much will the investment be worth after 10 years?
zepelin [54]

Answer:

$2,753.79

Step-by-step explanation:

Compound Interest Formula

\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}

where:

  • A = final amount
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • P = $2,000
  • r = 3.25% = 0.0325
  • n = 1
  • t = 10

Substitute the given values into the formula and solve for A:

\implies \sf A=2000\left(1+\frac{0.0325}{1}\right)^{(1 \times 10)}

\implies \sf A=2000(1.0325)^{10}

\implies \sf A=2753.788608...

Therefore, the value of the investment after 10 years will be $2,753.79 to the nearest cent.

8 0
2 years ago
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