The answer is 6:15, but if u need to simplify the answer would be 2:5.
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
x>-6
Step-by-step explanation:
The expression you need to solve for this is: 2x+15>3
For now pretend that the > is a = and solve as you normally would for x.
Subtract 15 from both sides
2x=-12
Divide by 2
x=-6
Put the > back in
x>-6
16, because all the other numbers are odd and 16 is even
Answer:
the statement which is not true is
~All Irrational Numbers are real Numbers
