5.b) If z^(1/2)=x^(1/2)+y^(1/2) , show that (x+y-z)^2=4xy
1 answer:
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Answer:
x = -2; y = 3
Step-by-step explanation:
5x + 4y = 2 (1)
3x + 3y = 3 (2)
Multiply (1) by 3 and (2) by 4
15x + 12y = 6 (3)
12x + 12y = 12 (4)
Subtract (4) from (3)
15x - 12x = 6 - 12
3x = -6
x = -6/3
x = -2
Substitute x = -2 into (1)
5x + 4y = 2
5(-2) + 4y = 2
-10 + 4y = 2
4y = 2 +10
4y = 12
y = 12/4
y = 3
The first error is when he multiplied equation (2) by 4
He didn't multiply the right hand side of the equation by 4
3x + 3y = 3 ×4
12x + 12y = 12
But he wrote
12x + 12y = 3
The the next error is subtracting the left hand side of the equation and adding the right hand side
15x + 12y = 6
12x + 12y = 3
He wrote
3x = 9
Instead of 3x = 3
