An example that illustrates speed
1 answer:
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Answer:
Step-by-step explanation:
To find the equation from a graphed function, you can substitute points into each equation to find the original:
A point on the graph is (2, 4). Substituting this into each equation, we get:
, which claims that 4 is equal to 30, which is incorrect.
, which claims that 4 is equal to 3/2, which is incorrect.
, which claims that 4 is equal to 4, which is correct.
We can test the third function further by taking another point on the graph, (3, 5), and substituting it into the function:
, which claims that 5 is equal to 5, which is correct.
The greatest common factor of 
and 
is
gcd(m*m*n*n, m*n*n*n) =m*n*n=
what we did, was to see how many m's and how many n's, each expression have, and then pick the smallest of each letter (factor).
the reason is that the common factor, must have enough m's and n's to divide the m's and n's of both expressions
so
also
thus, n is equal to 3
Answer: A)3
is
gcd(m*m*n*n, m*n*n*n) =m*n*n=
what we did, was to see how many m's and how many n's, each expression have, and then pick the smallest of each letter (factor).
the reason is that the common factor, must have enough m's and n's to divide the m's and n's of both expressions
so
also
thus, n is equal to 3
Answer: A)3