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Flauer [41]
3 years ago
12

Evaluate 1.80/Y for y= 0.009 express your answer is in simplest form.

Mathematics
1 answer:
igomit [66]3 years ago
3 0

Evaluate 1.80/Y for y= 0.009

We replace 0.009 for y

So fraction becomes \frac{1.80}{0.009}

Now , to simplify the fraction we try to remove the decimal from denominator

0.009 have three digits after the decimal point, so we multiply by 1000 to remove the decimal point. Multiply top and bottom by 1000 to make equivalent fraction.

\frac{1.80*1000}{0.009*1000}

\frac{1800}{9} = 200

Answer is 200

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How do i do this help
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I don't know if u can see it, but there.
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Find two positive real numbers whose product is a maximum. (enter your answers as a comma-separated list.) the sum of the first
Vladimir [108]
<span>the sum of the first and three times the second is 54.

x + 3y = 54 

3y = 54 - x 

y=  54 /3  -  x  /  3  = 18 -x /3

</span>xy = x  (18 -x /3) =  18x   -  x^2  / 3  =  - 1/3 x ^ 2  + 18 x 
<span>

</span><span>since a<0, it is concave downward, and the vertex is the maximum value. That vertex occurs at x= - b /2a = (-18) / (-2/3) = 12
</span>

<span>The first number is x=12.
The second is y = </span><span>18 -x /3 = 18- 12/ 3 = 18  - 4 = 14 </span>
5 0
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