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2 years ago

How much does 1 liter of water weigh

Physics

1 answer:

Zinaida [17]2 years ago

8 0

Weight = (mass) x (gravity)

On Earth ...

Weight = (1 kg) x (9.8 m/s^2)

Weight = 9.8 Newtons

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The information on a can of soda indicates that the can contains 355 mL. The mass of a full can of soda is 0.369 kg, while an em

Vilka [71]

Answer:

$\rho=995.50\ kg.m^{-3}$

$\bar w=9765.887\ N.m^{-3}$

$s=0.9955$

Explanation:

Given:

volume of liquid content in the can, $v_l=0.355\ L=3.55\times 10^{-4}\ L$

mass of filled can, $m_f=0.369\ kg$

weight of empty can, $w_c=0.153\ N$

So, mass of the empty can:

$m_c=\frac{w_c}{g}$

$m_c=\frac{0.153}{9.81}$

$m_c=0.015596\ kg$

Hence the mass of liquid(soda):

$m_l=m_f-m_c$

$m_l=0.369-0.015596$

$m_l=0.3534\ kg$

Therefore the density of liquid soda:

$\rho=\frac{m_l}{v_l}$ (as density is given as mass per unit volume of the substance)

$\rho=\frac{0.3534}{3.55\times 10^{-4}}$

$\rho=995.50\ kg.m^{-3}$

Specific weight of the liquid soda:

$\bar w=\frac{m_l.g}{v_l}=\rho.g$

$\bar w=995.5\times 9.81$

$\bar w=9765.887\ N.m^{-3}$

Specific gravity is the density of the substance to the density of water:

$s=\frac{\rho}{\rho_w}$

where:

$\rho_w=$ density of water

$s=\frac{995.5}{1000}$

$s=0.9955$

3 0

2 years ago

Read 2 more answers

Which of the following diagrams correctly shows the electron configuration of Sulfur, with atomic number 16?

nika2105 [10]

Answer:

Diagram C

Explanation:

We are given that Sulfur with atomic number 16.

We have to find that which diagram shows the electronic configuration of sulfur.

S=16

Its Diagram C

6 0

3 years ago

Read 2 more answers

A carbon resistor is to be used as a thermometer. On a winter day when the temperature is 4.00°C, the resistance of the carbon r

dusya [7]

Answer:

28 degree C

Explanation:

We are given that

$T_1=4.00^{\circ}$

$R_1=217.7 \Ohm$

$R_2=215.1\Ohm$

$\alpha=-5.00\times 10^{-4}C^{-1}$

We have to find the temperature on a spring day when resistance is 215.1 ohm.

We know that

$\alpha(T_2-T_1)=\frac{R_2}{R_2}-1$

Using the formula

$-5.00\times 10^{-4}(T_2-4)=\frac{215.1}{217.7}-1$

$-5\times 10^{-4}(T_2-4)=0.988-1=-0.012$

$T_2-4=\frac{0.012}{5\times 10^{-4}}=24$

$T_2=24+4=28^{\circ}C$

Hence, the temperature on a spring day 28 degree C.

7 0

3 years ago

A copper bar of length h and electric resistance r slides with negligible friction on metal rails that have negligible electric

Elanso [62]

I think math is the best idea

3 0

3 years ago

A car travelling 10m/s increases its speed to 20m/s over a time of 4s. What is the acceleration of the car? A car is traveling a

Alexxx [7]

Answer:

Explanation:

Acceleration is the change in velocity with respect to time.

Acceleration = change in velocity/Time

Acceleration = final velocity - initial velocity/Time

Given initial velocity = 10m/s

Final velocity = 20m/s

Time taken = 4s

Acceleration = 20-10/4

Acceleration = 10/4

Acceleration =2.5m/s²

For the second part of the question:

Given parameters

initial velocity = 15m/s

acceleration = -3m/s²

time = 4seconds

a = v-u/t

-3 = v-15/4

cross multiply

-12 = v-15

add 15 from both sides

-12+15 = v-15+15

3 = v

Hence the final velocity of the car is 3m/s

6 0

3 years ago