The answer for this question should be "false".
Answer:
The non-relativistic kinetic energy of a proton is 
The relativistic kinetic energy of a proton is 
Explanation:
Given that,
Mass of proton 
Speed
We need to calculate the kinetic energy for non relativistic
Using formula of kinetic energy

Put the value into the formula


We need to calculate the kinetic energy for relativistic
Using formula of kinetic energy



Hence, The non-relativistic kinetic energy of a proton is 
The relativistic kinetic energy of a proton is 
Answer:
False
Explanation:
It is located in the little dipper whose stars are more faint.
<span>The answer is: ultraviolet
The energy (E) of a photon is directly proportional to its frequency f, by Planck's
formula: E = hf, where h is Planck's constant (6.625 * 10**-34 joule-second).
The frequency is inversely proportional to the wavelength w by: f = c/w, where
c is the speed of light, 3.0 * 10**8 meters per second.
Combine these formulas and we see that the energy is inversely proportional to
the wavelength by: E = hc/w
If the energy is inversely proportional to the wavelength, a photon with twice the
energy has half the wavelength of our 442-nm. photon in this example.
So its wavelength is 221 nm. which is in the ultraviolet range.</span>
Answer:
x = 5.79 m
Explanation:
given,
mass of the car = 39000 Kg
spring constant = 5.7 x 10⁵ N/m
acceleration due to gravity = 9.8 m/s²
height of the track = 25 m
length of spring compressed = ?
using conservation of energy
potential energy is converted into spring energy




x = 5.79 m
the spring is compressed to x = 5.79 m to stop the car.