Question

A pitcher throws a softball toward home plate. When the ball hits the catcher’s mitt, its horizontal velocity is 32 meters/second. The softball’s velocity goes to 0 meters/second in 0. 8 seconds when caught. If the softball has a mass of 0. 2 kilograms, what’s the force of the impact? Use F = ma, where. The force of the impact is newtons.

Answer 1

The force of impact of the softball at the given conditions is 8 N.

The given parameters:

• Horizontal velocity of the ball, v = 32 m/s
• Change in time of motion of the ball, Δt = 0.8 s
• Mass of the ball, m = 0.2 kg

The force of impact of the softball is calculated by applying Newton's second law of motion as follows;

$F = ma\\\\F = m \times \frac{\Delta v}{\Delta t} \\\\F = 0.2 \times \frac{32 - 0}{0.8 - 0} \\\\F = \frac{0.2 \times 32}{0.8} \\\\F = 8 \ N$

Thus, the force of impact of the softball at the given conditions is 8 N.

Learn more about Newton's second law of motion here: brainly.com/question/25307325