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balu736 [363]
2 years ago
5

A pitcher throws a softball toward home plate. When the ball hits the catcher’s mitt, its horizontal velocity is 32 meters/sec

ond. The softball’s velocity goes to 0 meters/second in 0. 8 seconds when caught. If the softball has a mass of 0. 2 kilograms, what’s the force of the impact? Use F = ma, where. The force of the impact is newtons.
Physics
1 answer:
vladimir1956 [14]2 years ago
7 0

The force of impact of the softball at the given conditions is 8 N.

The given parameters:

  • <em>Horizontal velocity of the ball, v = 32 m/s</em>
  • <em>Change in time of motion of the ball, Δt = 0.8 s</em>
  • <em>Mass of the ball, m = 0.2 kg</em>

The force of impact of the softball is calculated by applying Newton's second law of motion as follows;

F = ma\\\\F = m \times \frac{\Delta v}{\Delta t} \\\\F = 0.2 \times \frac{32 - 0}{0.8 - 0} \\\\F = \frac{0.2 \times 32}{0.8} \\\\F = 8 \ N

Thus, the force of impact of the softball at the given conditions is 8 N.

Learn more about Newton's second law of motion here: brainly.com/question/25307325

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<h2>Hopefully u will satisfy with my answer of ur question..!!</h2>

<h2>Have a nice day ahead dear..!!</h2>
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0.132 x 1.25 - .143 x 1.14 = 1.03 cos43 x .143 - v cos θ

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Applying law of conservation of momentum along direction perpendicular to direction of original motion

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