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liq [111]
3 years ago
9

How many millimeters are there in 3.00 meters?

Chemistry
1 answer:
lyudmila [28]3 years ago
8 0

Answer:

3000000

Explanation:

3×1000000=3000000

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Mass can be created and destroyed.
Musya8 [376]

Answer:

Conservation of Energy and Mass

The law of conservation of mass states that in a chemical reaction mass is neither created nor destroyed. ... Similarly, the law of conservation of energy states that the amount of energy is neither created nor destroyed.

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3 years ago
Is atomic weight a whole number or not a whole number
steposvetlana [31]

Answer:

Atomic mass of an element is not a whole number because It contains isotopes. For example, chlorine has two isotopes 1735Cl and 1737Cl with natural abundances in the approximate ratio of 3:1. Hence, the average atomic mass of chlorine is approximately 35.5 g/mol.

Hope this helps! If so please mark brainliest and rate/heart if it did to help my account out!!

3 0
4 years ago
One molecule of glucose makes 36 molecules of atp how many molecules of glucose are needed to make 1800 molecules of atp
pogonyaev
You would need exactly 50 molecules of glucose. 
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4 years ago
What is atomic theory?​
shusha [124]

Answer: the theory that all matter us made up of tiny invisible particles. Hope that help you out :)

Explanation:

3 0
3 years ago
Read 2 more answers
how many molecules of sulfuric acid are in a spherical raindrop of diameter 6.0 mm if the acid rain has a concentration of 4.4 *
Vitek1552 [10]

Answer:

The number of moles =

Moles=4.97\times 10^{-8}

The number of molecules =

Molecules = 2.99\times 10^{16}

Explanation:

Volume of the sphere is given by :

V=\frac{4}{3}\pi r^{3}

here, r = radius of the sphere

radius=\frac{diameter}{2}

radius=\frac{6.0}{2}

Radius = 3 mm

r = 3 mm

1 mm = 0.01 dm (1 millimeter = 0.001 decimeter)

3 mm = 3 x 0.01 dm = 0.03 dm

r = 0.03 dm

<em>("volume must be in dm^3 , this is the reason radius is changed into dm"</em>

<em>"this is done because 1 dm^3 = 1 liter and concentration is always measured in liters")</em>

V=\frac{4}{3}\pi 0.03^{3}

V=\frac{4}{3}\pi 2.7\times 10^{-5}

V=1.13\times 10^{-4}dm^{3}

V=1.13\times 10^{-4}L   (1 L = 1 dm3)

Now, concentration "C"=

C=4.4\times 10^{-4}moles/liter  

The concentration is given by the formula :

C=\frac{moles}{Volume(L)}

This is also written as,

Moles = C\times Volume

Moles=1.13\times 10^{-4}\times 4.4\times 10^{-4}

Moles=4.97\times 10^{-8}moles

One mole of the substance contain "Na"(= Avogadro number of molecules)

So, "n"  mole of substance contain =( n x Na )

N_{a}=6.022\times 10^{23}

Molecules =

Molecule=4.97\times 10^{-8}\times 6.022\times 10^{23}

Molecules = 2.99\times 10^{16} molecules

7 0
3 years ago
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