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timofeeve [1]
3 years ago
15

Acetaldehyde (CH3CHO) undergoes a Wolf-Kishner reaction, which is the addition of hydrazine (H2NNH2) with subsequent addition of

a base and heat. In this reaction, the aldehyde is __________, resulting in a(n) __________ product.
Chemistry
1 answer:
Anarel [89]3 years ago
6 0

Answer:

Reduced, alkane

Explanation:

Wolf-Kishner reaction is a type of reduction reaction in which aldehydes and ketones are reduced to their corresponding alkane in the presence of a base.

This reaction occurs at high temperature.

Alkane formed has a same number of carbon as aldehyde and ketone.

If acetaldehyde undergoes a Wolf-Kishner reaction in the presence of base and heat, then ethane is formed. Nitrogen is formed as a byproduct.

Here, acetaldehyde is reduced to form ethane.

So, acetaldehyde undergoes a Wolf-Kishner reaction, which is the addition of hydrazine  with subsequent addition of a base and heat. In this reaction, the aldehyde is reduced, resulting in alkane product.

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8 0
2 years ago
How much energy (heat) is required to convert 248 g of water from 0 oC to 154 oC? Assume that the water begins as a liquid, that
Nuetrik [128]

Answer:

The total heat required is 691,026.36 J

Explanation:

Latent heat is the amount of heat that a body receives or gives to produce a phase change. It is calculated as: Q = m. L

Where Q: amount of heat, m: mass and L: latent heat

On the other hand, sensible heat is the amount of heat that a body can receive or give up due to a change in temperature. Its calculation is through the expression:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the change in temperature (Tfinal - Tinitial).

In this case, the total heat required is calculated as:

  • Q  for liquid water.  This is, raise 248 g of liquid water from O to 100 Celsius. So you calculate the sensible heat of water from temperature 0 °C to 100° C

Q= c*m*ΔT

Q=4.184\frac{J}{g*C} *248 g* (100 -0 )C

Q=103,763.2 J

  • Q  for phase change from liquid to steam. For this, you calculate the latent heat with the heat of vaporization being 40 and being 248 g = 13.78 moles (the molar mass of water being 18 g / mol, then\frac{248 g}{18 \frac{g}{mol} } =13.78 moles )

Q= m*L

Q=13.78moles*40.79 \frac{kJ}{mol}

Q=562.0862 kJ= 562,086.2 J (being 1 kJ=1,000 J)

  • Q for temperature change from  100.0 ∘ C  to  154 ∘ C, this is, the sensible heat of steam from 100 °C to 154°C.

Q= c*m*ΔT

Q=1.99\frac{J}{g*C} *248 g* (154 - 100 )C

Q=25,176.96 J

So, total heat= 103,763.2 J + 562,086.2 J + 25,176.96 J= 691,026.36 J

<u><em>The total heat required is 691,026.36 J</em></u>

8 0
3 years ago
What is the theoretical yield of Ca(OH)2, in grams, if 31.8 g of CaO is hydrolyzed (reacted) in an excess of water?
Fiesta28 [93]

The theoretical yield of Ca(OH)₂ : 42.032 g

<h3>Further explanation</h3>

Given

31.8 g of CaO

Required

The theoretical yield of Ca(OH)₂

Solution

Reaction

CaO + H₂O⇒Ca(OH)₂

mol CaO (MW=56 g/mol) :

= mass : MW

= 31.8 g : 56 g/mol

= 0.568

From equation, mol Ca(OH)₂ = mol CaO = 0.568

Mass Ca(OH)₂ (MW=74 g/mol) :

= 0.568 x 74

= 42.032 g

6 0
3 years ago
A flask containing 855 grams of water was heated. If the temperature of the water was raised from 21.0 to 85.0 degrees Celsius,
marin [14]

Answer:

The heat absorbed by the water is 228,948.48 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

In this way, between heat and temperature there is a direct proportional relationship (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also decreases; and the same happens when either of the two decreases .). The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

  • c= 4.184 \frac{J}{g*C}
  • m=855 g
  • ΔT= Tfinal - Tinitial= 85 °C - 21°C= 64 °C

Replacing:

Q= 4.184 \frac{J}{g*C} *855 g* 64 C

Solving:

Q= 228,948.48 J

<u><em>The heat absorbed by the water is 228,948.48 J</em></u>

6 0
2 years ago
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