Given:
35.0 mL of acid with an unknown concentration
24.6 mL of 0.432 M base
Required:
Concentration of the acid
Solution:
M1V1 = M2V2
M1 (35.0 mL of acid)
= (0.432 M base) (24.6 mL
of base)
V1 = (0.432
M base) (24.6 mL of base) /
(35.0 mL of acid)
M1 = 0.304 M of acid
Answer:
+5
Explanation:
The oxidation number of phosphorus can be obtained as follows:
H4P2O7 = 0
4(+1) + 2P + 7(—2) = 0
4 + 2P —14 = 0
Collect like terms
2P = 14 — 4
2P = 10
Divide both side by 2
P = 10/2
P = +5
The oxidation number of phosphorus is +5
Answer:
8 should be placed in front of SO₂.
Explanation:
The easiest way to solve this question is by writing the <u>entire</u> balanced equation:
4FeS₂ + 11O₂ -> 2Fe₂O₃ + 8SO₂
We can achieve this by first balancing the Fe, then S, and finally the O.
We can also double check our answer by counting the number of each element on both sides:
-Reactants: 4 Fe, 8 S, 22 O
-Products: 4 Fe 8 S, 22 O
Since they match, our equation is balanced, and the coefficient in front of SO₂ is 8.
Answer:
option C = Reactant: 4NH₃ + 6NO → product: 5N₂ + 6H₂O
Explanation:
Chemical equation:
NH₃ + NO → N₂ + H₂O
Balanced chemical equation:
4NH₃ + 6NO → 5N₂ + 6H₂O
Ammonia is react with nitrogen mono oxide and produced nitrogen and water.
Ammonia and nitrogen monoxide are reactants while water and nitrogen are product.
Four number of moles of ammonia react with six nitrogen monoxide and produced five mole of nitrogen and six mole of water.
