The correct question is
<span>What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3
</span>
we have that
point (1,-2)
slope m=1/3
so
y-y1=m*(x-x1)-----> y+2=(1/3)*(x-1)----> multiply by 3---> 3y+6=x-1
x-3y-1-6=0------> x-3y-7=0
the answer is
<span>x - 3y - 7 = 0</span>
91.5 is the perimeter. It's just 5a.
Answer:
[2(p + 1)]/q
Step-by-step explanation:
logx 2 = p
logx 7 = q
log7 4x² = log7 (2x)²
= (logx (2x)²)/(logx 7)
= (2 logx 2x)/(logx 7)
= (2 logx 2 + 2 logx x)/(logx 7)
= (2p + 2)/q
= [2(p + 1)]/q
Use you graphing calculator in the y equals button
