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Whitepunk [10]
3 years ago
15

What is -5+3x-16-10x

Mathematics
2 answers:
Fittoniya [83]3 years ago
6 0
<span><span><span><span><span>−5</span>+<span>3x</span></span>+<span>−16</span></span>+<span>−<span>10x
</span></span></span></span>
Combine like terms
(3x+−10x)+(−5+−16)<span>
<span><span>
=−<span>7x</span></span>+<span>−<span>21</span></span></span></span>
Vedmedyk [2.9K]3 years ago
3 0
Ok here I go lol
X=8
Hope I helped
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I dont know what to do here​
Ipatiy [6.2K]

Answer:

1. acute

2.acute

Step-by-step explanation:

8 0
2 years ago
Select the correct difference. -3z 7 - (-5z 7) 2z7 8z14 -2z7 2z
timofeeve [1]
-3z^7 - (-5z^7) = -3z^7 + 5z^7 = 2z^7
6 0
3 years ago
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Which is more likely to happen?
horsena [70]
Number one is more likely to happen.
how likely is it? equally likely as not likely
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2 years ago
Which list contains values that are all part of the solution set of the graphed inequality? 2, 1, 3. 9, 4 2001. 3, 4, 0, 2. 6 1.
olya-2409 [2.1K]

The inequality is,

0\leq x\leq 2001.3

we have given that the solution set

2, 1, 3. 9, 4 2001. 3, 4, 0, 2. 6 1. 1, 1. 5, 19. 7, 8. 2 11, 1, 48. 5, 7.

here we have given that all the values of x are positive and

Which is the smallest point in above set?

0

and

Which is the highest point in the above set?

2001.3

Therefore,

we have a=0 and b=2001.2

Our equality lie in a and b

Therefore,

a\leq x\leq b

Plug the value of a and b we get

0\leq x\leq 2001.3

Therefore we get the inequality is,

0\leq x\leq 2001.3

To learn more about the inequality visit:

brainly.com/question/24372553

8 0
2 years ago
A bicycle lock has a four-digit code. The possible digits, 0 What is the probability that the lock code will begin with
nika2105 [10]

Answer:

0.1-0.6

Step-by-step explanation:

First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities

the second digit is any of the remaining 9, after having picked one. 

and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

so 

P(first digit is five)=

b. What is the probability that the lock code will not contain the number 0? 

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6

8 0
3 years ago
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