Answer:
a) 0.96
b) 0.016
c) 0.018
d) 0.982
e) x = 2
Step-by-step explanation:
We are given with the Probability density function f(x)= 2/x^3 where x > 1.
<em>Firstly we will calculate the general probability that of P(a < X < b) </em>
P(a < X < b) = =
= { Because }
= =
= =
a) Now P(X < 5) = P(1 < X < 5) {because x > 1 }
Comparing with general probability we get,
P(1 < X < 5) = = = 0.96 .
b) P(X > 8) = P(8 < X < ∞) = 1/ - 1/∞ = 1/64 - 0 = 0.016
c) P(6 < X < 10) = = = 0.018 .
d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)
= + (1/ - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982
e) We have to find x such that P(X < x) = 0.75 ;
⇒ P(1 < X < x) = 0.75
⇒ = 0.75
⇒ = 1 - 0.75 = 0.25
⇒ = ⇒ = 4 ⇒ x =
Therefore, value of x such that P(X < x) = 0.75 is 2.
The range is: 35-60
The IQR is: 11
This value is the first 25%
IQR= interquartile range
Hope this helps ;)
Answer:
Area = 64π
Area \: = \pi {r}^{2}Area=πr
2
64 \: \pi \: = \pi {r}^{2}64π=πr
2
{r}^{2} = \dfrac{64\pi}{\pi}r
2
=
π
64π
{r}^{2} = 64r
2
=64
r \: = \: \sqrt{64} = 8r=
64
=8
Radius = 8 units
Finding the Diameter -
Diameter = Radius x 2 = 8 x 2 = 16 .
\bold{Diameter \: is \: 16 \: units}Diameteris16units
Answer:
20 lbs
Step-by-step explanation:
2/5ths of the food would be 20 pounds because:
2/5 * 50 = 20
2/10ths of the food would be 10 pounds because:
2/10 * 50 = 10
If we add those two together, we would get the total amount that the dog ate, which would be 30 pounds. SInce the dog ate 30 pounds of food out of the 50 pounds, there would be 20 pounds left in the bag at the end of two months:
50- ( 20+ 10) = 20