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Whitepunk [10]
3 years ago
15

What is -5+3x-16-10x

Mathematics
2 answers:
Fittoniya [83]3 years ago
6 0
<span><span><span><span><span>−5</span>+<span>3x</span></span>+<span>−16</span></span>+<span>−<span>10x
</span></span></span></span>
Combine like terms
(3x+−10x)+(−5+−16)<span>
<span><span>
=−<span>7x</span></span>+<span>−<span>21</span></span></span></span>
Vedmedyk [2.9K]3 years ago
3 0
Ok here I go lol
X=8
Hope I helped
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How do i solve 7x^{2} +11y^{2} =40
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Answer:

Step-by-step explanation:

There is no solution as you have two variables and only one equation. The best you can do is solve for one variable as a function of the other.

7x^2+11y^2=40\\ \\ 11y^2=40-7x^2\\ \\ y^2=\frac{40-7x^2}{11}\\ \\ y=\sqrt{\frac{40-7x^2}{11}}

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Carmen has 10 boxes of seashells with 6 seashells in each box. She gave away 5 seashells. Which steps can you use to find the nu
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Solve the equation below, then check your answer by seeing if LS = RS. Show your work!
Allushta [10]

Answer:

m = 4

Step-by-step explanation:

6m + 7 = 31 \\ 6m + 7 - 7 = 31 - 7 \\ 6m = 24 \\  \frac{6m}{6}  =  \frac{24}{6}  \\ m = 4

check

6m + 7 = 31 \:  \:  \:  \:  \: m = 4 \\ 6(4)  + 7 = 31 \\ 24 + 7 = 31 \\ 31 = 31

7 0
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Through (-1,4) and a perpendicular to 4y-2x=12
mart [117]

Answer:

<h2>y = -2x + 2 → 2x + y = 2</h2>

Step-by-step explanation:

\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-\text{slope}\\b-\text{y-intercept}\\\\\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\\text{then}\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\k\ ||\ l\iff m_1=m_2

\text{We have the equation of a line in the standard form:}\ Ax+By=C.\\\\\text{Convert to the slope-intercept form:}\\\\4y-2x=12\qquad\text{add}\ 2x\ \text{to the both sides}\\\\4y-2x+2x=2x+12\\\\4y=2x+12\qquad\text{divide both sides by 4}\\\\\dfrac{4y}{4}=\dfrac{2x}{4}+\dfrac{12}{4}\\\\y=\dfrac{1}{2}x+3\to\boxed{m_1=\dfrac{1}{2}}

\text{Therefore}\ m_2=-\dfrac{1}{\frac{1}{2}}=-2.\\\\\text{Put the value of the slope and the coordinates of the given point (-1, 4)}\\\text{to the equation of a line:}\\\\4=-2(-1)+b\\\\4=2+b\qquad\text{subtract 2 from the both sides}\\\\4-2=2-2+b\\\\2=b\to b=2\\\\\bold{FINALLY:}\ y=-2x+2

\text{Convert to the standard form:}\\\\y=-2x+2\qquad\text{add}\ 2x\ \text{to the both sides}\\\\y+2x=-2x+2x+2\\\\2x+y=2

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4 years ago
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