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Stells [14]
4 years ago
10

A spacecraft drifts through space at a constant velocity. suddenly a gas leak in the side of the spacecraft causes it to constan

tly accelerate in a direction perpendicular to the initial velocity. the orientation of the spacecraft does not change, so the acceleration remains perpendicular to the original direction of the velocity. what is the shape of the path followed by the spacecraft?
Physics
1 answer:
Ivanshal [37]4 years ago
6 0

Here space craft is moving with constant velocity

Now due to gas leakage it will have acceleration perpendicular to velocity

it is given that acceleration is always perpendicular to velocity

So it will neither increase nor decrease the velocity

it will only change the direction of the motion

so it is the centripetal acceleration of the space craft

in this case we will say that path of the space craft will be circular path

<em>So it will perform Uniform Circular Motion and its path will be a circle</em>

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An object moves with constant acceleration 3.10 m/s2 and over a time interval reaches a final velocity of 12.4 m/s. If its initi
Harrizon [31]

Answer:

Explanation:

Given:

a = 3.10 m/s^2

vf = 12.4 m/s

vi = -6.2 m/s

t = (vf - vi)/a

= (12.4 + 6.2)/3.1

= 6 s

displacement = (vf - vi)*t

= (12.4 + 6.2) * 6

= 111.6 m.

3 0
3 years ago
Read 2 more answers
13. Calculate the total heat energy in Joules needed to convert 20 g of substance X from -10°C to 70°C?
sergeinik [125]

The heat required to convert the unknown substance X from one phase to another is 1600 J times the specific heat of that substance.

Explanation:

The heat energy required to convert a substance or to heat up or increase the temperature of a substance can be obtained from the specific heat formula.

As per this formula, the heat energy applied should be equal to the product of  mass of the substance with temperature gradient and also with specific heat of the substance. Basically, the heat provided to increase or convert a substance should be more than the specific heat of the substance.

Q = mc del T

Since, here the mass of the substance X is given as m = 20g and the temperature change is given from -10°C to 70°C.

Then ΔT = (70-(-10))=70+10=80°C.

As the substance is unknown, the specific heat of that substance can also not be determined. Hence keep it as C.

Q = 20*C*80

Q = 1600C J

Thus, the heat required to convert the unknown substance X from one phase to another is 1600 J times the specific heat of that substance.

5 0
3 years ago
If an 800.-kg sports car slows to 13.0 m/s to check out an accident scene and the 1200.-kg pick-up truck behind him continues tr
Alborosie

Answer: 20.2 m/s

Explanation:

From the question above, we have the following data;

M1 = 800kg

M2 = 1200kg

V1 = 13m/s

V2 = 25m/s

U (common velocity) =?

M1V1 + M2V2 = (M1 + M2). U

(800*13) + (1200*25) = (800+1200) * U

10400 + 30000 = 2000u

40400 = 2000u

U = 40400 / 2000

U = 20.2 m/s

5 0
3 years ago
Read 2 more answers
After landing on an unexplored Klingon planet, Spock tests for the direction of the magnetic field by firing a beam of electrons
BARSIC [14]

Answer:

Magnetic field is in south west direction .

Explanation:

Let us represent various direction by  i , j, k . i representing east , j representing north and k representing vertically upward direction .

magnetic field is represented vectorially as follows

B = B₀ ( - i - j )

In the first case velocity of electron

v = v k

Force = q ( v x B )

= -e [ vk x B₀ ( - i - j ) ]

= evB₀ ( j -i )

Direction of force is north -west .

In the second case velocity of electron

v = vj

Force = -e [ vj x B₀ ( - i - j ) ]

= - evB₀ k

force is downward

In the third case, velocity of electron

v = v( -j +i )

Force = -e [ v( -j +i ) x B₀ ( - i - j ) ]

= 2 evB₀ k

Force is upward.

3 0
3 years ago
A rock is thrown by applying a force of 2.50N while doing 6.00J of work. Over what distance was the force applied?
maksim [4K]

Answer:

\boxed {\boxed {\sf 2.40 \ meters}}

Explanation:

Work is the product of force and distance, so the formula is:

W= F \times d

The work is 6.00 Joules, but

  • 1 Joule (J) is equal to 1 Newton meter (N*m).
  • Therefore, the work of 6.00 J is equal to 6.00 N*m

The force is 2.50 Newtons.

The known values are:

  • W= 6.00 N*m
  • F= 2.50 N

Substitute the values into the formula.

6.00 \ N*m= 2.50 \ N *d

We are solving for distance, so we must isolate the variable, d. It is being multiplied by 2.50 Newtons and the inverse of multiplication is division. Divide both sides by 2.50 N.

\frac {6.00 \ N*m}{2.50 \ N}=\frac{2.50 \ N * d}{2.50 \ N}

\frac {6.00 \ N*m}{2.50 \ N}=d

The units of Newtons cancel out.

\frac {6.00 m}{2.50 }=d

2.40 \ m =d

The force was applied to the rock over a distance of <u>2.40 meters</u> and choice <u>C</u> is correct.

6 0
3 years ago
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