2 years ago

Make the following prefix conversions. 0.001s =ms

1 answer:

4 0

Answer:

To convert a millisecond measurement to a second measurement, divide the time by the conversion ratio. The time in seconds is equal to the milliseconds divided by 1,000.

Explanation:

hope it helps

You might be interested in

Un autocar que circula a 81 km/h frena uniformemente con una aceleración de -4,5 m/s2.

horsena [70]

Answer:

a) $\Delta x=56.25 m$

b) imagen adjunta

Explanation:

a) Primero debemos hacer la conversión de 81 km/h a m/s, esto es 22.5 m/s.

Ahora, usando la ecuacion cinemática, en un movimiento acelerado tenemos:

$v_{f}^{2}=v_{0}^{2}+2a \Delta x$

Queremos encontrar la posición hasta detenerse, osea vf = 0.

$\Delta x=\frac{-v_{0}^{2}}{2a}$

$\Delta x=\frac{-22.5^{2}}{-2*4.5}$

$\Delta x=56.25 m$

b) Para este caso el gráfico se encuentra adjunto.

Espero que te sirva de ayuda!

Download pdf

8 0

3 years ago

What is the average speed of an object with a total distance traveled of 45 meters in 50 seconds

Anettt [7]

Answer: 0.9m/s

Explanation:

Use equation for speed:

V=S/t

S-distance; S=45m

t-time; t=50 s

V=S/t

V=45m/50s

V=0.9 m/s

7 0

3 years ago

Which statement correctly describes the relationship between frequency and wavelength?

liraira [26]

For a wave:

v = fλ

v is the velocity, f is the frequency, and λ is the wavelength.

Assuming the velocity of the wave doesn't change...

If you increase its frequency, its wavelength will shorten.

5 0

3 years ago

Read 2 more answers

A truck is driving over a scale at a weight station. When the front wheels drive over the scale, the scale reads 5800 N. When th

aev [14]

Answer:

$x_2=1.60m$

Explanation:

From the Question We are told that

Initial Force $F_1=5800N$

Final Force $F_2=6500N$

Distance between the front and rear wheels \triangle x=3.20 m

Since

$\triangle x=3.20 m$

Therefore

$x_1+x_2=3.20$

$x_1=3.20-x_2$

Generally the equation for The center of mass is at x_2 is mathematically

given by

$x_2 =\frac{(F_1x_1+F_2x_2)}{(F_1+F_2)}$

$x_2=3.20F_1-\frac{x_2F_1+F_2x_2}{(F_1+F_2)}$

$2*F_1*x_2 =3.20F_1$

$x_2=1.60m$

6 0

2 years ago

A 1400kg car is moving at a speed of 25m/s. How much KE does the car have?

Nady [450]

Answer:

437500Joules

Explanation:

Kinetic energy=1/2mvsquare

1/2 x 1400 x 25 x25

kinetic energy= 437500Joules

6 0

3 years ago