How to make green colour with two colours?
2 answers:
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Answer:
- 0.279 m/s
Explanation:
mass (m1) = 1150 kg
mass (m2) = 1900 kg
impulse (J) = 200 N.s
With what relative speed do the two parts separate because of the detonation?
since both parts separate, their relative speed = speed of m1 + speed of m2
- speed of m1 =
=
= 0.174 m/s
- speed of m2 =
= 0.105 m/s
- relative speed = 0.174 + 0.105 = 0.279 m/s
Answer:
a) At 0.20 m, the magnitude of the field is 675.0 kV
The direction of the field is acting outwards from the center of the charged spheres
b) At 0.10 m, the magnitude of the field is 135 kV
The direction is acting outwards from the center of the charged spheres
c) At 0.025 m
The magnitude of the field, V = -270.0 kV
The direction of the field is inwards, towards the center of the charged spheres
Explanation:
The charged spherical shell parameters are;
The charge on the inner sphere, q₁ = -1.50 × 10⁻⁶ C
The radius of the inner shell, R₁ = 0.050 m
The charge on the outer sphere, q₂ = +4.50 × 10⁻⁶ C
The radius of the outer shell, R₂ = 0.15 m
Let 'r', represent the distance at which the electric field is measured, the following relationships can be obtained;
When r < R₁ < R₂,
When R₁ < r < R₂,
When R₁ < R₂ < r,
a) When r = 0.20 m, we have;
R₁ < R₂ < r, therefore
By plugging in the values, we get;
Therefore, the magnitude of the field, V = 675.0 kV
The direction of the field is outwards
b) When r = 0.10 m, we have;
When R₁ < r < R₂, therefore;
By plugging in the values, we get;
Therefore, the magnitude of the field, V = 135 kV
The direction of the field is outwards from the center
c) When r = 0.025 m, we have;
When r < R₁ < R₂, therefore;
By plugging in the values, we get;
Therefore, the magnitude of the field, V = -270.0 kV
The direction of the field is inwards, towards the center of the charged spheres.