Answer:
For the first question, to determine the total number of molecules of nitrogen dioxide, first make use of the molar mass of the nonpolar compound and then use that to find the total number of moles and then subsequently after make use of the ratio for the Avogadro's number to determine the total number of molecules of this compound.
For the final question, do the inverse, where we make use of the molecules of the compound and then use Avogadro's number to determine the moles of the compound and then use the same molar mass of the compound to determine the grams of the Nitrogen Dioxide.
B. 100 meters is only equal to 1 hectometer.
Metals in their pure form are highly flammable. In this item, we are given with the pure magnesium metal in ribbon form reacting with oxygen in the combustion process. The equation that would best illustrate this given is,
2Mg + O₂ --> 2MgO
In this item, we are to determine the amount of MgO that can will be formed.
Magnesium
(4.81 g)(1 mol Mg/24.31 g Mg)(2 mol MgO/2 mol Mg)(40.3 g MgO/1 mol MgO)
= 7.97 g MgO
Oxygen
(7.46 g)(1 mol O2/32 g O2)(2 mol MgO/1 mol O2)(40.3 g MgO/1 mol MgO)
= 18.79 g MgO
This means that the amount of MgO produced is 7.97 g.
Answer: 1+
Justification:
The ionization energy is the amount of energy needed to loose electrons and becomes ions.
The first ionization energy is the energy needed to liberate one one electron and form the ion with oxidation state 1+.
The second ionization energy is the energy to release a second electron and form the ion with oxidation state 2+.
The third ionization energy is the energy to leave a third electron free and form the ion with oxidation state 3+.
The relatively low first ionization energy of element 2, shows it it will lose an electron easily to form the ion with oxidations state 1+.
The second and third ionization energies are very high meaning that the ions with oxidation staes 2+ and 3+ will not be formed.
Therefore, the answer is that the expected oxidation state for the most common ion of element 2 is 1+.