Caused by the earths tilt
Bromine atoms usually end up with SEVEN valence electrons.
Bromine belongs to group 17 i.e. halogen group. Its atomic number is 35. The electron configuration of Bromine is 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁵. In the last shell, we see 4s²4p⁵, thus 2+5 = 7 valence electrons are present.
Here's how you would solve it. The process should be the same for the others.
Answer:
1.346 v
Explanation:
1) Fist of all we need to calculate the standard cell potential, one should look up the reduction potentials for the species envolved:
(oxidation) → E°=0.337 v
(reduction) → E°=1.679 v
(overall) +8H^{+}_{(aq)}→ E°=1.342 v
2) Nernst Equation
Knowing the standard potential, one calculates the nonstandard potential using the Nernst Equation:
Where 'R' is the molar gas constant, 'T' is the kelvin temperature, 'n' is the number of electrons involved in the reaction and 'F' is the faraday constant.
The problem gives the [red]=0.66M and [ox]=1.69M, just apply to the Nernst Equation to give
E=1.346