when heat gained = heat lost
when AL is lost heat and water gain heat
∴ (M*C*ΔT)AL = (M*C*ΔT) water
when M(Al) is the mass of Al= 225g
C(Al) is the specific heat of Al = 0.9
ΔT(Al) = (125.5 - Tf)
and Mw is mass of water = 500g
Cw is the specific heat of water = 4.81
ΔT = (Tf - 22.5)
so by substitution:
∴225* 0.9 * ( 125.5 - Tf) = 500 * 4.81 * (Tf-22.5)
∴Tf = 30.5 °C
A because if you multiple it, you will be moving the decimal one time
The answer your looking for is a)
-please give me brainliest answer
Answer:
<h3>The answer is 0.5 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula
From the question we have
We have the final answer as
<h3>0.5 g/mL</h3>
Hope this helps you
Answer:
low
Explanation:
We were informed in the question that the student had incorrectly recorded the mass of cup + sample as 2.20 g but inadvertently used 2.00 g in the calculations.
This error will cause a slight decrease in the mass of water and ultimately decrease the number of moles of water in the hydrate.
What i am saying is that the number of moles of water obtained in the calculation will be artificially low.
