2Al + 3Fe(NO₃)₂ = 3Fe + 2Al(NO₃)₃
m=245 g
w=0.805 (80.5%)
M{Fe(NO₃)₂}=179.857 g/mol
M(Fe)=55.847 g/mol
1. the mass of salt in solution is:
m{Fe(NO₃)₂}=mw
2. the proportion follows from the equation of reaction:
m(Fe)/3M(Fe)=m{Fe(NO₃)₂}/3M{Fe(NO₃)₂}
m(Fe)=M(Fe)m{Fe(NO₃)₂}/M{Fe(NO₃)₂}
m(Fe)=M(Fe)mw/M{Fe(NO₃)₂}
m(Fe)=55.847*245*0.805/179.857= 61.24 g
Answer:
1.25 mol LiF
Explanation:
5.00 M solution means
5.00 mol LiF in 1 L solution=1000mL
x mol LiF in 250 mL
x = 5.00*250/1000 = 1.25 mol LiF
Answer:
The volume of STP will be 0.03 plss mark me brainliest
Answer:
Water ______________________________________________