Answer:
Explanation:
<u>1) Data:</u>
a) M = 0.5 M
<u>Note</u>: since the question is about volume (liters) and moles of solute, the correct unit for the concentration of the hydroxide solution is M (upper case) which is the unit for molarity. Lower case m is used for molality, and you cannot calculate the volume of the solution unless you know some other data, e.g. density of the solution.
b) n = 2
c) V (in liters) = ?
<u>2) Formula:</u>
Molarity is the number of moles of solute per liter of solution:
<u>3) Solution:</u>
a) Clear V from the formula: V (in liters) = M / n
b) Substitute: V (in liters) = 2 moles / 0.5M = 4 liters ← answer
A. There is very little empty space in a gas in not part of the kinetic molecular theory of gases.
Explanation:
The kinetic molecular theory of gases follows following points:
Kinetic energy does not change or get dissipated when gas molecules collide with each other. No attraction or repulsion between gas particles is observed. Particles of gas are moving randomly in all directions. Temperature increase cause the rapid movement of gas particles.The gas particles are placed very far from each other as compared to liquid.
The empty space in a gas is large because gas gets compressed in the small volume of the container also.
Answer:
El termopar B presenta un mayor grado de dispersión y también es más preciso. ... (c) La estimación para T = 175 ° C es probablemente la más cercana al valor real, porque el ... (cm3). Flujo de masa. Velocidad. (kg / min). Diferencia. Duplicar. (Di). Yo y yo. 2. 1 ... atm de gas. 2. 2. 2 f. 3. 2 f f. 30 14,7 lb 20 pulg. 4 14,7 lb 24 pulg 392 lb 7,00 10 lb pulg.
Answer:
1120 gm
Explanation:
6. Consider the reaction: CzHo (g) + 02 (8) - 4 CO2(g) + 6H2O (1)
(a) Balance the equation.
(b) How many grams of oxygen are required to react with 10 moles of ethane for a complete
combustion reaction?
FIRST, CORRECT THE EQUATION THEN BALANCE
2C2H6(G) + 7O2------------> 4CO2 + 6H2O
so for 10 moles of ethane, we need
7 X 5 = 35 MOLES O2
=35 MOLES O2
O2 HAS A MOLAR MASS OF 2X16 = 32 gm
35 MOLES OF O2 HAS A MASS OF 35 X 32 =1120 gm
