Answer:
Explanation:
Formula for the calculation of no. of Mol is as follows:
Molecular mass of Ag = 107.87 g/mol
Amount of Ag = 5.723 g
Molecular mass of S = 32 g/mol
Amount of S = 0.852 g
Molecular mass of O = 16 g/mol
Amount of O = 1.695 g
In order to get integer value, divide mol by smallest no.
Therefore, divide by 0.02657
Therefore, empirical formula of the compound =
Decay constant of the process 1×10^(-12) day^(-1).
<h3>What is decay constant?</h3>
A radioactive nuclide's probability of decay per unit time is known as its decay constant, which is expressed in units of s1 or a1. As a result, as shown by the equation dP/P dt =, the number of parent nuclides P declines with time t. Nuclear forces are about 1,000,000 times more powerful than electrical and molecular forces in their ability to bind protons and neutrons. The strength of the bonds holding the radioactive element are likewise indifferent to the decay probabilities and's, in addition to being unaffected by temperature and pressure. The decay constant is related to the nuclide's T 1/2 half-life by T 1/2 = ln 2/.
To know more about decay constant:
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Each 100 cm3 of air, constitutes 78cm3 nitrogen, 21cm3 oxygen and 1cm3 constitutes of other gases like Argon, ozone, carbon dioxide and water vapour in small amounts.
Answer:
[H3O+] = 1.4*10^-5 M
pH = 4.85
[OH-] = 7.08*10^-10
Explanation:
As pH is a measure of hydronium H3O concentration, simply substitute [H3O+] into the following equation:
pH = -log[H+]
pH = -log(1.4*10^-5)
pH = 4.853871...
Round to 2-3 sig figs due to only being given data with 2 significant figures
pH = 4.85
One method to get to [OH-] is to turn pH into pOH and then use inverse functions to get [OH-]
pH + pOH = 14
4.85 + pOH = 14
pOH = 9.15
Then to get [OH-] from pOH:
pOH = -log[OH-]
9.15 = -log[OH-]
-9.15 = log[OH-]
10^(-9.15) = [OH-]
7.07945784 * 10^-10 = [OH]
Round based on given significant figures again:
7.08*10^-10 = [OH-]
(Feel free to add any questions & I'll be sure to reply if clarification is needed)
