B)The concentration of the acid (C₁) is the same as that of the base (C₂).
V₁=V₂
n(acid)=C₁V₁
n(base)=C₂V₂
HX + YOH = YX + H₂O
n(acid)=n(base)
C₁V₁=C₂V₂
C₁=C₂
Bit.my/3a8Nt8n here’s the link for the answer
Answer:
81 L gas
General Formulas and Concepts:
<u>Ideal Gas Law</u>
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 3.6 mols gas at STP
[Solve] volume (L) of gas
<u>Step 2: Convert</u>
- [DA] Set up:

- [DA] Multiply [Cancel out units]:

<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
80.64 L gas ≈ 81 L gas
Answer:
endoplasmic reticulum:
✔ helps in the production and movement of materials
Golgi body:
✔ packages and distributes materials in and out of cell
mitochondrion:
✔ supplies energy that the cell uses
ribosome:
✔ produces proteins for the cell
Explanation:
took test :D
Answer: The strength of an acid or alkali depends on the degree of dissociation of the acid or alkali in water. The degree of dissociation measures the percentage of acid molecules that ionise when dissolved in water. He could use universal indicators or litmus paper for this.
i hope this helps you!