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Sergio [31]
3 years ago
7

Assume that y varies directly as x. If y = 3, when x = 15, find the value of y when x = 75. A) 3 B) 15 C) 30 D) 45

Mathematics
2 answers:
Leni [432]3 years ago
8 0

Answer:

Step-by-step explanation:

Answer:y=15

 3      y

___=___

15    75

cross multiply

15y=225

divide both sides by 15

y=15

konstantin123 [22]3 years ago
6 0

Answer:

y=15 B

Step-by-step explanation:

First divide 15 from 75, which equals 5.  Then multiply 3 by 5.

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Write the equation in y-intercept form slope 2 passes through point (5,-2)
Alenkinab [10]
<h2>Answer</h2>

The equation is y = 2x - 12

<h2>Explanation</h2>

Equation in slope intercept form is

y = mx + b

Where,

m = slope

b = y-intercept

Putting the value of slope in this equation:

y = 2x + b

From this we can solve the equation for b

b = y - 2x

b = -2 - 2(5)

b = -12

Now, the equation of y-intercept becomes

y = 2x - 12


5 0
4 years ago
Nvm I got it now lol
Usimov [2.4K]

Answer:

nice bro good for you :)

Step-by-step explanation:

3 0
2 years ago
Two brothers decide that a 21-hour task is to be divided so thst the older brother works twice as long as the younger brother. H
lyudmila [28]

Answer:

14 hours

Step-by-step explanation:

Let's call the task 3x

The older bro does twice as younger so it would be 2x long and younger brother work x long

Since the totsl of work is 3x = 21 x woul be 21÷3 = 7

the older brother must work 2 × 7 = 14 hours long

3 0
3 years ago
Read 2 more answers
The oldest child in a family of four children is twice as old as the yougest. The two middle children are 12 and 15 years old. I
vesna_86 [32]

Answer:

8 years old

Step-by-step explanation:

oldest= 16

8+12+15+16= 51

51/4 = 12.73 ( average)

3 0
3 years ago
How much money invested at 5% compounded continuously for 3 years will yield at $820?
Oduvanchick [21]

Answer:

Percentage of interest at which the money is invested = 5%

Time for which the money is invested = 3 years

The final amount after 3 years = $820

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We can conclude that the principal amount invested was $708.35.


3 0
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