For each expression, use the distributive property to write an equivalent expression.

You are skateboarding at a pace of 30 meters every 5 seconds. your friend is in-line skating at a pace of 9 meters every 2 secon

AnnyKZ [126]

In order to graph the relationship, we will need to write the expression as the equation of a straight line as shown:

d = mt + b

d is the distance covered

t is the time taken

m is the speed

If you are skateboarding at a pace of 30 meters every 5 seconds. your friend is in-line skating at a pace of 9 meters every 2 seconds, this can be written as (5, 30) and (2, 9)

Get the slope of the line:

m = (9-30)/(2-5)

m = -21/-3

m = 7

Substitute m = 7 and the coordinate (2, 9) into the equation y = mt + b

9 = 7(2) + b

9 = 14 + b

b = -5

The required equation to plot will be expressed as y = 7t - 5

Plot the required graph

Learn more here: brainly.com/question/17003809

4 0

3 years ago

What is the factorization??

aivan3 [116]

We first find the zeros of the function , the zeros of the function are those at which points the graph of the function crosses or touches the x axis

here we can see in the graph that graph crosses the x axis at two points , 1 and 7

So the zeros of the function are

x=1 and x=7

It means the factor are

(x-1) and (x-7)

So the factorization is given by

(x-1)(x-7)

7 0

3 years ago

Question 17/23

disa [49]

Answer:

60%

Step-by-step explanation:

Formula:

Percentage decrease = (amount of decrease)/(original price)

✪ Solve ✪

3.85 - 1.54/3.85 x 100

2.31/3.85 x 100 = 60%

Hence, Percent decrease is 60%

~Lenvy

6 0

2 years ago

Please help with geometry. 20 points, and another question worth 98 on my profile!

vovikov84 [41]

Answer:

Part 1) m∠1 =(1/2)[arc SP+arc QR]

Part 2) $PR^{2} =PS*PT$

Part 3) PQ=PR

Part 4) m∠QPT=(1/2)[arc QT-arc QS]

Step-by-step explanation:

Part 1)

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

we have

m∠1 -----> is the inner angle

The arcs that comprise it and its opposite are arc SP and arc QR

so

m∠1 =(1/2)[arc SP+arc QR]

Part 2)

we know that

The Intersecting Secant-Tangent Theorem, states that the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

so

In this problem we have that

$PR^{2} =PS*PT$

Part 3)

we know that

The Tangent-Tangent Theorem states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments

so

In this problem

PQ=PR

Part 4)

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

In this problem

m∠QPT -----> is the outer angle

The arcs that it encompasses are arc QT and arc QS

therefore

m∠QPT=(1/2)[arc QT-arc QS]

4 0

2 years ago

A figure is translated using the rule (x, y) - (x - 3, y + 6).

Strike441 [17]

Answer:

Left 3 units and up 6 units

Step-by-step explanation:

6 0

3 years ago