1/4 bc if you take the fraction 3/12 and simply it’s 1/4
<h2>
Answer:</h2>

<h2>
Step-by-step explanation:</h2>
The question in this problem is:
<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>
<em />
First of all, let's name the first variable
which is the smaller number. Accordingly, the lager number will be
given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

So:
1. The sum of 2 consecutive integers can be written as:

2. Nine times the smaller and 5 times the larger can be written as:

Finally, the whole statement:
The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:


The two numbers are:

The hypotenuse would be square root of 41
Answer:
I hope I know but I need help my self
7/15 ÷ 3/5 =
= 7/15 * 5/3 =
= 7/3 * 1/3 = (after simplifying)
= <u>7/9</u>
Correct answer: A
Just keep in mind that dividing one fraction by another fraction is as much as multiplying the same fraction by an inverse of the second one.