All categories

3 years ago

5x+10=7x+4 what is the answer to this equation

Mathematics

1 answer:

Gennadij [26K]3 years ago

4 0

answer: $x = 5$

work:

$5x+10=7x+4$ | subtract 5x and move it over to the 7x, and solve

$10 = 2x + 4$ | subtract 4 and move it over to the 10, and solve

$6 = 2x$ | divide by 2

$3 = x$ | final answer

hope this helps! ❤ from peachimin

You might be interested in

Write an equivalent expression for 3/5x + 2/5 + 3/5x

never [62]

= 3/5(x) + 3/5(x) + 2/5
= 6/5(x) + 2/5
= 2/5 (3x+1)

I hope that is what you are looking for.

6 0

2 years ago

Simplify the square root of 272

vladimir2022 [97]

If you are looking for the square root, which I’m assuming. It’s 4 square root of 17, or 16.492

8 0

3 years ago

Please help me on number 2

goldenfox [79]

On number 2 2 times -3 is 6

8 0

3 years ago

What is the 103rd term of the arithmetic sequence

UNO [17]

Answer:

option B: 31/4

Step-by-step explanation:

Given

-3/4, -2/3 , -7/12, -1/2...........

General formula for arithmeti sequence to find nth term is

a_n = a_1 + (n-1) d

first term a_1 = -3/4

We find out common difference 'd'

Lets find the difference of first two terms

$\frac{-2}{3} -\frac{-3}{4} = \frac{-8}{12} +\frac{9}{12} =\frac{1}{12}$

common difference is 1/12

now we need to find 103rd term

$a_n = a_1 + (n-1) d$

First term is -3/4, d= 1/12

$a_{103} = \frac{-3}{4}+(103-1)\frac{1}{12}$

$a_{103} = \frac{-3}{4}+(102)\frac{1}{12}$

$a_{103} = \frac{-3}{4}+\frac{34}{4}$

$a_{103} = \frac{-3+34}{4}$

$a_{103} = \frac{31}{4}$

5 0

2 years ago

Read 2 more answers

5 more than a number s 5+s or s+5

cestrela7 [59]

Either one works according to me.

5 0

2 years ago