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3 years ago

Identify and equation in point slope form for the line perpendicular to y= -3x+7 that passes through 2,-4

Mathematics

1 answer:

Gnesinka [82]3 years ago

6 0

Perpendicular slope: 1/3

y + 4 = 1/3(x - 2)

y + 4 = 1/3x - 2/3

y + 12/3 = 1/3x - 2/3

y = 1/3x - 14/3

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Bill bought a new cellular phone. His monthly bill will be $32.99 each month which includes 100 minutes of use. Additional minut

Sunny_sXe [5.5K]

Answer: option D is the correct answer.

Step-by-step explanation:

Let m represent the total number of minutes that the phone is used in a month.

Let C represent the amount of the bill for using m minutes.

His monthly bill will be $32.99 each month which includes 100 minutes of use. Additional minutes will cost $0.19 per minute. It means that the cost of additional minutes is

0.19(m - 100). Therefore, the linear model representing the amount of the bill would be

C = 0.19(m - 100) + 32.99

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3 years ago

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Dovator [93]

Answer:

Step-by-step explanation:

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3 years ago

What is the radius of a circle in which a 30° arc is 2 inches long?

marysya [2.9K]

It would be 1 inch and 15 degree arc due to the act that the radius is half.

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3 years ago

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A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha

White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

$\frac{dB}{dt} = rB-k$

$\Rightarrow \frac{dB}{dt} - rB=-k$ .......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor $=e^{\int p(t) dt$

$=e^{\int (-r)dt$

$=e^{-rt}$

Multiplying the integrating factor the both sides of equation (1)

$e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}$

$\Rightarrow e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt$

Integrating both sides

$\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt$

$\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C$ [ where C arbitrary constant]

$\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}$

Initial condition B=7864 when t =0

$\therefore 7864= \frac{k}{r} - Ce^0$

$\Rightarrow C= \frac{k}{r} -7864$

Then the general solution is

$B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}$

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

$B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}$

$\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0$

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

=$1573.17

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3 years ago

3 less than c in numbers

Ira Lisetskai [31]

Answer:

Step-by-step explanation:

3<3

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