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3 years ago

7

Pittsburgh International airport had approximately 714,587 passengers in august 2009. write a number that is greater than 714,58

7

1 answer:

OLga [1]3 years ago

8 0

Answer:

800,000

Step-by-step explanation:

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A survey asked 20 mobile phone dealers how many mobile phones were sold during the previous week. Their answers are displayed in

Sidana [21]

The best type of chart for quickly deriving the mode of a sample data is called the Stem-and-Leaf Plot.

<h3>What is a Stem-and-Leap Plot?</h3>

In statistics, the Stem-and-Leaf Plot is an easy-to-make easy-to-read kind of graph that is derived from the table holding the sample data.

The Box-and-Whisker Plot on the other hand is best for visually depicting the five-number summary of any set of data, which are:

Minimum
First Quartile
Median (Second Quartile)
Third Quartile; and
Maximum.

It is to be noted that referenced plots are not indicated hence, the general answer.

Learn more about Stem-and-Leaf Plot at:
brainly.com/question/8649311
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8 0

1 year ago

The resting heart rate of 60 patients is shown in the frequency table below.

Murrr4er [49]

The standard deviation is 9.27. The typical heart rate for the data set varies from the mean by an average of 9.27 beats per minute.

<h3>How to determine the standard deviation of the data set?</h3>

The dataset is given as:

Heart Rate Frequency

60 1

65 3

70 4

75 12

80 8

85 15

90 9

95 5

100 3

Calculate the mean using

Mean = Sum/Count

So, we have

Mean = (60 * 1 + 65 * 3 + 70 * 4 + 75 * 12 + 80 * 8 + 85 * 15 + 90 * 9 + 95 * 5 + 100 * 3)/(1 + 3 + 4 + 12 + 8 + 15 + 9 + 5 + 3)

Evaluate

Mean = 82.25

The standard deviation is

$\sigma = \sqrt{\frac{\sum f(x - \bar x)^2}{\sum f -1}}$

So, we have:

SD = √[1 * (60 - 82.25)^2 + 3 * (65 - 82.25)^2 + 4 * (70 - 82.25)^2 + 12 * (75 - 82.25)^2 + 8 * (80 - 82.25)^2 + 15 * (85 - 82.25)^2 + 9 * (90 - 82.25)^2 + 5 * (95 - 82.25)^2 + 3 * (100 - 82.25)^2)]/[(1 + 3 + 4 + 12 + 8 + 15 + 9 + 5 + 3 - 1)]

This gives

SD = √85.9533898305

Evaluate

SD = 9.27

Hence. the standard deviation is 9.27. The typical heart rate for the data set varies from the mean by an average of 9.27 beats per minute.

Read more about standard deviation at:

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5 0

1 year ago

Is the median always sometimes or never one of the data values. explain

blondinia [14]

It can somteimes be one of the data values. When there's an odd set of numbers, the median will always be one of the data values. When there's a even set of numbers, the median will sometimes be one of the data values.
Even:
2, 3, 4, 5, 6, 7
Now, we need to find the number between 4 and 5, which is 4.5, 4.5 doesn't show up in the data set.
2,3, 5, 5, 6, 7
The middle of 5 and 5 is 5 since it's the same number. 5 does show up in the data set.
So, the median sometimes is one of the data values.

6 0

3 years ago

Read 2 more answers

Two cargo ships spot a signal fire on a small island. The captains know they are 140 feet

Irina18 [472]

The distance from Ship B to the signal fire at point C is $405.4 \mathrm{ft}$

Explanation:

It is given that two ships A and B are at a distance 140 ft from each other.

The angle formed by ship A is 82º and the angle formed by ship B is 78º.

To determine the distance from ship B to the signal fire at point C, we need to know the another angle.

Hence, we have,

$\begin{aligned}\angle A+\angle B+\angle C &=180^{\circ} \\82^{\circ}+78^{\circ}+\angle C &=180^{\circ} \\160^{\circ}+\angle C &=180^{\circ} \\\angle C &=20^{\circ}\end{aligned}$

Now, we shall solve the problem using the law of sines,

$\frac{\sin A}{a}=\frac{\sin C}{c}$

Substituting the values, we have,

$\frac{\sin 82^{\circ}}{a}=\frac{\sin 20^{\circ}}{140}$

$\frac{0.9903}{a}=\frac{0.3420}{140}$

Simplifying, we get,

$a=\frac{0.9903 \times 140}{0.3420}$

$a=405.4$

Thus, the distance from Ship B to the signal fire at point C is $405.4 \mathrm{ft}$

4 0

3 years ago

Please help me with this question.

Evgen [1.6K]

Answer:

$\purple{ \boxed{\frac{d^{2} y}{dx ^{2} } = \frac{132}{ {x}^{13} } }}$

Step-by-step explanation:

$y = \frac{1}{ {x}^{11} } \\ y = {x}^{ - 11} \\ \frac{dy}{dx} = \frac{d}{dx} {x}^{ - 11} \\ \frac{dy}{dx} = - 11{x}^{ - 11 - 1} \\ \frac{dy}{dx} = - 11{x}^{ - 12} \\ \\ \frac{d}{dx} \bigg(\frac{dy}{dx} \bigg) = \frac{d}{dx} ( - 11 {x}^{ - 12} ) \\ \\ \frac{d^{2} y}{dx ^{2} } = - 11\frac{d}{dx} ( {x}^{ - 12} ) \\ \\ \frac{d^{2} y}{dx ^{2} } = - 11( - 12{x}^{ - 13} ) \\ \\ \frac{d^{2} y}{dx ^{2} } = 132{x}^{ - 13} \\ \\ \huge \red{ \boxed{\frac{d^{2} y}{dx ^{2} } = \frac{132}{ {x}^{13} } }}$

8 0

2 years ago