Question

A new youth sports center is being built in oak valley. The perimeter of the rectangular playing field is 522 yards. The length of the field is 4 yards less than quadruple the width. What are the dimensions of the playing​ field?

Answer 1

It is given in the question that

A new youth sports center is being built in oak valley. The perimeter of the rectangular playing field is 522 yards. The length of the field is 4 yards less than quadruple the width.

Let the width be x yards . And the length is 4 yards less than 4times the width .

So length is

$(4x-4) yards$

And the perimeter is the sum of all sides, that is

$x+4x-4+x+4x-4+x = 522$

Combining the like terms,

$10x -8 = 522$

Adding 8 to both sides

$10x=530 \\ x = 53 yards$

Therefore the width is 53 yards, and length is 4 less than 4 times the width, that is

$4*53-4 = 208 yards$