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Kisachek [45]
3 years ago
9

If sinθ= 4/5 in quadrant II, what is cosθ?

Mathematics
2 answers:
AURORKA [14]3 years ago
7 0

Answer:

cos theta = -3/5

Step-by-step explanation:

jok3333 [9.3K]3 years ago
5 0

Answer:  cos\theta=-\dfrac{3}{5}

<u>Step-by-step explanation:</u>

sin\theta = \dfrac{y}{r}=\dfrac{4}{5}

<u>Step 1:</u>  Use Pythagorean Theorem: x² + y² = r²  to find the x-value

x² + 4² = 5²

x² + 16 = 25

      x² = 9

       x = 3

<u>Step 2:</u> Use the Quadrant to determine the sign of the x-value

                 Quadrant II                          Quadrant I

                     (--, +)                                     (+, +)

                 Quadrant III                          Quadrant IV

                     (--, --)                                     (+, --)

<em>x is negative in Quadrant II</em>

cos\theta=\dfrac{x}{r}=\large\boxed{-\dfrac{3}{5}}

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